The potential difference in open circuit for a cell is 2.2 volts. When a 4-ohm resistor is connected between its two electrodes the potential difference becomes 2 volts. The internal resistance of the cell will be :
1. 1 ohm
2. 0.2 ohm
3. 2.5 ohm
4. 0.4 ohm
A cell whose e.m.f. is 2 V and internal resistance is 0.1 Ω, is connected with a resistance of 3.9 Ω. The voltage across the cell terminal will be :
1. 0.50 V
2. 1.90 V
3. 1.95 V
4. 2.00 V
n identical cells each of e.m.f. E and internal resistance r are connected in series. An external resistance R is connected in series to this combination. The current through R is
1.
2.
3.
4.
A cell of internal resistance r is connected to an external resistance R. The current will be maximum in R, if :
1. R = r
2. R < r
3. R > r
4. None of these
Two identical cells send the same current in 2 Ω resistance, whether connected in series or in parallel. The internal resistance of the cell should be
1. 1 Ω
2. 2 Ω
3.
4. 2.5 Ω
The internal resistances of the two cells shown are 0.1 Ω and 0.3 Ω. If R = 0.2 Ω, the potential difference across the cell :
1. B will be zero
2. A will be zero
3. A and B will be 2V
4. A will be > 2V and B will be < 2V
The figure shows a network of currents. The magnitude of currents is shown here. The current i will be
1. 3 A
2. 13 A
3. 23 A
4. – 3 A
A battery of emf \(E\) and internal resistance \(r\) is connected to a variable resistor \(R\) as shown below. Which one of the following is true?
1. | The potential difference across the terminals of the battery is maximum when \(R=r.\) |
2. | The power delivered to the resistor is maximum when \(R=r.\) |
3. | The current in the circuit is maximum when \(R=r.\) |
4. | The current in the circuit is maximum when \(R>>r.\) |
Consider the circuit given here with the following parameters E.M.F. of the cell = 12 V. Internal resistance of the cell = 2 Ω. Resistance R = 4 Ω. Which one of the following statements is true.
1. Rate of energy loss in the source is = 8 W
2. Rate of energy conversion in the source is 16 W
3. Power output in R is = 8 W
4. Potential drop across R is = 16 V
The current in the arm \(CD\) of the circuit will be:
1. \(i_{1} + i_{2}\)
2. \(i_{2} + i_{3}\)
3. \(i_{1} + i_{3}\)
4. \(i_{1} - i_{2} + i_{3}\)