In the figure, current through the 3 Ω resistor is 0.8 ampere, then potential drop through 4 Ω resistor is 

(1) 9.6 V

(2) 2.6 V

(3) 4.8 V

(4) 1.2 V

What is the equivalent resistance between A and B in the figure below if R = 3 Ω 

(1) 9 Ω

(2) 12 Ω

(3) 15 Ω

(4) None of these

What is the equivalent resistance between A and B 

(1) $\frac{2}{3}R$

(2) $\frac{3}{2}R$

(3) $\frac{R}{2}$

(4) 2 R

What is the equivalent resistance of the circuit​​​​​?

1. \(6~\Omega\)
2. \(7~\Omega\)
3. \(8~\Omega\)
4. \(9~\Omega\)

The equivalent resistance of the circuit shown in the figure is :

(1) 8 Ω

(2) 6 Ω

(3) 5 Ω

(4) 4 Ω

In the given figure, the equivalent resistance between the points A and B is :

(1) 8 Ω

(2) 6 Ω

(3) 4 Ω

(4) 2 Ω

A battery of emf 10 V and internal resistance 3 Ω is connected to a resistor as shown in the figure. If the current in the circuit is 0.5 A. then the resistance of the resistor will be 

(1) 19 Ω

(2) 17 Ω

(3) 10 Ω

(4) 12 Ω

The potential drop across the 3Ω resistor is 

(1) 1 V

(2) 1.5 V

(3) 2 V

(4) 3 V

If each resistance in the figure is \(9~\Omega\), then the reading of the ammeter is:

1. \(5~\text{A}\)
2. \(8~\text{A}\)
3. \(2~\text{A}\)
4. \(9~\text{A}\)

Two wires of equal diameters, of resistivities ρ₁ and ρ₂ and lengths l₁ and l₂, respectively, are joined in series. The equivalent resistivity of the combination is :

(1) $\frac{{\rho }_1{l}_1+{\rho }_2{l}_2}{l_1+l_2}$

(2) $\frac{{\rho }_1{l}_2+{\rho }_2{l}_1}{l_1-l_2}$

(3) $\frac{{\rho }_1{l}_2+{\rho }_2{l}_1}{l_1+l_2}$

(4) $\frac{{\rho }_1{l}_1-{\rho }_2{l}_2}{l_1-l_2}$