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Q. No.An electric dipole is placed as shown in the figure.
The electric potential (in \(10^2~\text{V}\)) at the point \(P\) due to the dipole is:
(\(\varepsilon_0=\) permittivity of free space and \(\dfrac{1}{4 \pi \varepsilon_0}=k\))
1.
\(\left(\dfrac{8}{3}\right)qk\)
2.
\(\left(\dfrac{3}{8}\right)qk\)
3.
\(\left(\dfrac{5}{8}\right)qk\)
4.
\(\left(\dfrac{8}{5}\right)qk\)
Subtopic: Energy of Dipole in an External Field |
63%
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NEET - 2023
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The equivalent capacitance of the arrangement shown in the figure is:
1. \(30~\mu \text{F}\)
2. \(15~\mu \text{F}\)
3. \(25~\mu\text{F}\)
4. \(20~\mu\text{F}\)
1. \(30~\mu \text{F}\)
2. \(15~\mu \text{F}\)
3. \(25~\mu\text{F}\)
4. \(20~\mu\text{F}\)
Subtopic: Combination of Capacitors |
71%
From NCERT
NEET - 2023
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If a conducting sphere of radius \(R\) is charged. Then the electric field at a distance \(r(r>R)\) from the centre of the sphere would be, (\(V=\) potential on the surface of the sphere):
| 1. | \(\dfrac{rV}{R^2}\) | 2. | \(\dfrac{R^2V}{r^3}\) |
| 3. | \(\dfrac{RV}{r^2}\) | 4. | \(\dfrac{V}{r}\) |
Subtopic: Electric Potential |
From NCERT
NEET - 2023
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The equivalent capacitance of the system shown in the following circuit is:
| 1. | \(9~{\mu \text{F}}\) | 2. | \(2~{\mu \text{F}}\) |
| 3. | \(3~{\mu \text{F}}\) | 4. | \(6~{\mu \text{F}}\) |
Subtopic: Combination of Capacitors |
82%
From NCERT
NEET - 2023
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Six charges \(+q,\) \(-q,\) \(+q,\) \(-q,\) \(+q\) and \(-q\) are fixed at the corners of a hexagon of side \(d\) as shown in the figure. The work done in bringing a charge \(q_0\) to the centre of the hexagon from infinity is:
(\(\varepsilon_0\text-\)permittivity of free space)
(\(\varepsilon_0\text-\)permittivity of free space)
| 1. | zero | 2. | \(\dfrac{-q^2}{4\pi\varepsilon_0d}\) |
| 3. | \(\dfrac{-q^2}{4\pi\varepsilon_0d}\Big(3-\dfrac{1}{\sqrt2}\Big)\) | 4. | \(\dfrac{-q^2}{4\pi\varepsilon_0d}\Big(6-\dfrac{1}{\sqrt2}\Big)\) |
Subtopic: Electric Potential Energy |
84%
From NCERT
NEET - 2022
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The effective capacitances of two capacitors are \(3~\mu \text{F}\) and \(16~\mu \text{F}\), when they are connected in series and parallel respectively. The capacitance of two capacitors are:
1. \(10 ~\mu \text{F}, ~6~\mu \text{F}\)
2. \(8 ~\mu \text{F}, ~8~\mu \text{F}\)
3. \(12~\mu \text{F},~ 4~\mu \text{F}\)
4. \(1.2~\mu \text{F},~1.8~\mu \text{F}\)
1. \(10 ~\mu \text{F}, ~6~\mu \text{F}\)
2. \(8 ~\mu \text{F}, ~8~\mu \text{F}\)
3. \(12~\mu \text{F},~ 4~\mu \text{F}\)
4. \(1.2~\mu \text{F},~1.8~\mu \text{F}\)
Subtopic: Combination of Capacitors |
78%
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NEET - 2022
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The distance between the two plates of a parallel plate capacitor is doubled, and the area of each plate is halved. If \(C\) is its initial capacitance, its final capacitance is equal to:
| 1. | \(2C\) | 2. | \(\dfrac{C}{2}\) |
| 3. | \(4C\) | 4. | \(\dfrac{C}{4}\) |
Subtopic: Capacitance |
80%
From NCERT
NEET - 2022
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When a particle with charge \(+q\) is thrown with an initial velocity \(v\) towards another stationary change \(+Q,\) it is repelled back after reaching the nearest distance \(r\) from \(+Q.\) The closest distance that it can reach if it is thrown with an initial velocity \(2v,\) is:
| 1. | \(\dfrac{r}{4}\) | 2. | \(\dfrac{r}{2}\) |
| 3. | \(\dfrac{r}{16}\) | 4. | \(\dfrac{r}{8}\) |
Subtopic: Electric Potential Energy |
71%
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NEET - 2022
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Three capacitors, each of capacitance \(0.3~\mu \text{F}\) are connected in parallel. This combination is connected with another capacitor of capacitance \(0.1~\mu \text{F}\) in series. Then the equivalent capacitance of the combination is:
1. \(0.9~\mu\text{F}\)
2. \(0.09~\mu\text{F}\)
3. \(0.1~\mu\text{F}\)
4. \(0.01~\mu\text{F}\)
1. \(0.9~\mu\text{F}\)
2. \(0.09~\mu\text{F}\)
3. \(0.1~\mu\text{F}\)
4. \(0.01~\mu\text{F}\)
Subtopic: Combination of Capacitors |
85%
From NCERT
NEET - 2022
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A hollow metal sphere of radius \(R\) is given \(+Q\) charges to its outer surface. The electric potential at a distance \(\dfrac{R}{3}\) from the centre of the sphere will be:
| 1. | \(\dfrac{1}{4\pi \varepsilon_0}\dfrac{Q}{9R}\) | 2. | \(\dfrac{3}{4\pi \varepsilon_0}\dfrac{Q}{R}\) |
| 3. | \(\dfrac{1}{4\pi \varepsilon_0}\dfrac{Q}{3R}\) | 4. | \(\dfrac{1}{4\pi \varepsilon_0}\dfrac{Q}{R}\) |
Subtopic: Electric Potential |
65%
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NEET - 2022
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