Select Question Set:
Q. No.The equivalent capacitance of the system shown in the following circuit is:
1.
\(9~{\mu \text{F}}\)
2.
\(2~{\mu \text{F}}\)
3.
\(3~{\mu \text{F}}\)
4.
\(6~{\mu \text{F}}\)
Subtopic: Combination of Capacitors |
83%
Level 1: 80%+
NEET - 2023
Hints
An electric dipole is placed as shown in the figure.
The electric potential (in \(10^2~\text{V}\)) at the point \(P\) due to the dipole is:
(\(\varepsilon_0=\) permittivity of free space and \(\dfrac{1}{4 \pi \varepsilon_0}=k\))
The electric potential (in \(10^2~\text{V}\)) at the point \(P\) due to the dipole is:
(\(\varepsilon_0=\) permittivity of free space and \(\dfrac{1}{4 \pi \varepsilon_0}=k\))
| 1. | \(\left(\dfrac{8}{3}\right)qk\) | 2. | \(\left(\dfrac{3}{8}\right)qk \) |
| 3. | \(\left(\dfrac{5}{8}\right)qk\) | 4. | \(\left(\dfrac{8}{5}\right)qk\) |
Subtopic: Energy of Dipole in an External Field |
64%
Level 2: 60%+
NEET - 2023
Hints
The equivalent capacitance of the arrangement shown in the figure is:
| 1. | \(30~\mu \text{F}\) | 2. | \(15~\mu \text{F}\) |
| 3. | \(25~\mu\text{F}\) |
4. | \(20~\mu\text{F}\) |
Subtopic: Combination of Capacitors |
72%
Level 2: 60%+
NEET - 2023
Hints
If a conducting sphere of radius \(R\) is charged. Then the electric field at a distance \(r(r>R)\) from the centre of the sphere would be, (\(V=\) potential on the surface of the sphere):
| 1. | \(\dfrac{rV}{R^2}\) | 2. | \(\dfrac{R^2V}{r^3}\) |
| 3. | \(\dfrac{RV}{r^2}\) | 4. | \(\dfrac{V}{r}\) |
Subtopic: Electric Potential |
50%
Level 3: 35%-60%
NEET - 2023
Hints
Six charges \(+q,\) \(-q,\) \(+q,\) \(-q,\) \(+q\) and \(-q\) are fixed at the corners of a hexagon of side \(d\) as shown in the figure. The work done in bringing a charge \(q_0\) to the centre of the hexagon from infinity is:
(\(\varepsilon_0\text-\)permittivity of free space)
(\(\varepsilon_0\text-\)permittivity of free space)
| 1. | zero | 2. | \(\dfrac{-q^2}{4\pi\varepsilon_0d}\) |
| 3. | \(\dfrac{-q^2}{4\pi\varepsilon_0d}\Big(3-\dfrac{1}{\sqrt2}\Big)\) | 4. | \(\dfrac{-q^2}{4\pi\varepsilon_0d}\Big(6-\dfrac{1}{\sqrt2}\Big)\) |
Subtopic: Electric Potential Energy |
84%
Level 1: 80%+
NEET - 2022
Hints
The effective capacitances of two capacitors are \(3~\mu \text{F}\) and \(16~\mu \text{F}\), when they are connected in series and parallel respectively. The capacitance of two capacitors are:
1. \(10 ~\mu \text{F}, ~6~\mu \text{F} \)
2. \(8 ~\mu \text{F}, ~8~\mu \text{F} \)
3. \(12~\mu \text{F},~ 4~\mu \text{F} \)
4. \(1.2~\mu \text{F},~1.8~\mu \text{F} \)
1. \(10 ~\mu \text{F}, ~6~\mu \text{F} \)
2. \(8 ~\mu \text{F}, ~8~\mu \text{F} \)
3. \(12~\mu \text{F},~ 4~\mu \text{F} \)
4. \(1.2~\mu \text{F},~1.8~\mu \text{F} \)
Subtopic: Combination of Capacitors |
79%
Level 2: 60%+
NEET - 2022
Hints
The distance between the two plates of a parallel plate capacitor is doubled, and the area of each plate is halved. If \(C\) is its initial capacitance, its final capacitance is equal to:
| 1. | \(2C\) | 2. | \(\dfrac{C}{2}\) |
| 3. | \(4C\) | 4. | \(\dfrac{C}{4}\) |
Subtopic: Capacitance |
81%
Level 1: 80%+
NEET - 2022
Hints
A positively charged particle \(+q\) is projected with speed \(v\) toward a fixed charge \(+Q,\) and rebounds after reaching a minimum distance \(r.\) What will be the new closest distance of approach if its initial velocity is doubled to \(2v\text{?}\)
| 1. | \(\dfrac{r}{4}\) | 2. | \(\dfrac{r}{2}\) |
| 3. | \(\dfrac{r}{16}\) | 4. | \(\dfrac{r}{8}\) |
Subtopic: Electric Potential Energy |
71%
Level 2: 60%+
NEET - 2022
Hints
Three capacitors, each of capacitance \(0.3~\mu \text{F}\) are connected in parallel. This combination is connected with another capacitor of capacitance \(0.1~\mu \text{F}\) in series. Then the equivalent capacitance of the combination is:
| 1. | \(0.9~\mu\text{F}\) | 2. | \(0.09~\mu\text{F}\) |
| 3. | \(0.1~\mu\text{F}\) | 4. | \(0.01~\mu\text{F}\) |
Subtopic: Combination of Capacitors |
85%
Level 1: 80%+
NEET - 2022
Hints
A hollow metal sphere of radius \(R\) is given \(+Q\) charges to its outer surface. The electric potential at a distance \(\dfrac{R}{3}\) from the centre of the sphere will be:
| 1. | \(\dfrac{1}{4\pi \varepsilon_0}\dfrac{Q}{9R}\) | 2. | \(\dfrac{3}{4\pi \varepsilon_0}\dfrac{Q}{R}\) |
| 3. | \(\dfrac{1}{4\pi \varepsilon_0}\dfrac{Q}{3R}\) | 4. | \(\dfrac{1}{4\pi \varepsilon_0}\dfrac{Q}{R}\) |
Subtopic: Electric Potential |
65%
Level 2: 60%+
NEET - 2022
Hints
Select Question Set:
© 2025 GoodEd Technologies Pvt. Ltd.