Aniline with excess of methyl iodide in the presence of sodium carbonate solution gives:

1. N, N, N−Trimethylanilinium carbonate.
2. N, N-Dimethylaniline.
3. N, N-Diethylaniline.
4. N, N, N−Triethylanilinium carbonate.

Subtopic: Amines - Preparation & Properties |

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Q294:

Given below are two statements:

Statement I:	Primary aliphatic amines react with HNO₂ to give unstable diazonium salts.
Statement II	Primary aromatic amines react with HNO₂ to form diazonium salts which are stable even above 300 K.

In the light of the above statements, choose the most appropriate answer from the options given below:

1.	Statement I is incorrect but Statement II is correct
2.	Both Statement I and II are correct
3.	Both Statement I and II are incorrect
4.	Statement I is correct but Statement II is incorrect

Subtopic: Diazonium Salts: Preparation, Properties & Uses |

51%

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Q295:

The product formed from the following reaction sequence is

1.		2.
3.		4.

Subtopic: Diazonium Salts: Preparation, Properties & Uses | Mechanism |

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Q296:

Match list-I with list-II:

	List-I (Amines)		List-II (pK_b values)
(a)	N-Methylmethanamine	(i)	9.30
(b)	Ammonia	(ii)	9.38
(c)	N-Methylaniline	(iii)	4.75
(d)	Benzenamine	(iv)	3.27

Choose the correct answer from the options given below:

	(a)	(b)	(c)	(d)
1.	(iv)	(ii)	(i)	(iii)
2.	(iv)	(iii)	(i)	(ii)
3.	(iii)	(iv)	(i)	(ii)
4.	(i)	(iv)	(iii)	(ii)

Subtopic: Amines - Preparation & Properties |

68%

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Q297:

The major product (P) formed in the following reaction sequence is :

1.		2.
3.		4.

Subtopic: Amines - Preparation & Properties |

67%

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Q298:

Match column I (Reaction) with column II (Product formed) and mark the appropriate choice:

	Column - I (Reaction)		Column - II (Product formed)
(a)	Gabriel synthesis	(i)	Benzaldehyde
(b)	Kolbe synthesis	(ii)	Ethers
(c)	Williamson synthesis	(iii)	Primary amines
(d)	Etard reaction	(iv)	Salicylic acid