The gravitational potential difference between the surface of a planet and 10 m above is 5 J/kg. If the gravitational field is supposed to be uniform, the work done in moving a 2 kg mass from the surface of the planet to a height of 8 m is
1. 2J
2. 4J
3. 6J
4. 8J
1. | TT is conserved |
2. | VV is always positive |
3. | EE is always negative |
4. | the magnitude of LL is conserved but its direction changes continuously |
In planetary motion, the areal velocity of the position vector of a planet depends on the angular velocity (ω)(ω) and the distance of the planet from the sun (r)(r). The correct relation for areal velocity is:
1. dAdt∝ωrdAdt∝ωr
2. dAdt∝ω2rdAdt∝ω2r
3. dAdt∝ωr2dAdt∝ωr2
4. dAdt∝√ωrdAdt∝√ωr
If AA is the areal velocity of a planet of mass M,M, then its angular momentum is:
1. | MAMA | 2. | 2MA2MA |
3. | A2MA2M | 4. | AM2AM2 |
Two bodies of masses m and 4m are placed at a distance r. The gravitational potential at a point on the line joining them where the gravitational field is zero is
1. -5Gmr−5Gmr
2. -6Gmr−6Gmr
3. -9Gmr−9Gmr
4. 0
Magnitude of potential energy (UU) and time period (T)(T) of a satellite are related to each other as:
1. T2∝1U3T2∝1U3
2. T∝1U3T∝1U3
3. T2∝U3T2∝U3
4. T2∝1U2T2∝1U2
A projectile fired vertically upwards with a speed v escapes from the earth. If it is to be fired at 45°° to the horizontal, what should be its speed so that it escapes from the earth?
1. v
2. v√2v√2
3. √2v√2v
4. 2v
Kepler's second law regarding constancy of the areal velocity of a planet is a consequence of the law of conservation of:
1. Energy
2. Linear momentum
3. Angular momentum
4. Mass
A point PP lies on the axis of a ring of mass MM and radius aa at a distance aa from its centre CC. A small particle starts from PP and reaches CC under gravitational attraction. Its speed at CC will be:
1. √2GMa√2GMa
2. √2GMa(1−1√2)√2GMa(1−1√2)
3. √2GMa(√2−1)√2GMa(√2−1)
4. zero
A projectile is fired upwards from the surface of the earth with a velocity kvekve where veve is the escape velocity and k<1k<1. If rr is the maximum distance from the center of the earth to which it rises and RR is the radius of the earth, then rr equals:
1. Rk2Rk2
2. R1−k2R1−k2
3. 2R1−k22R1−k2
4. 2R1+k22R1+k2