A spring-block system oscillates with a time period \(T\) on the earth's surface. When the system is brought into a deep mine, the time period of oscillation becomes \(T'.\) Then one can conclude that:
1. \(T'>T\)
2. \(T'<T\)
3. \(T'=T\)
4. \(T'=2T\)

Subtopic:  Combination of Springs |
 69%
From NCERT
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A particle executes simple harmonic oscillations under the effect of small damping. If the amplitude of oscillation becomes half of the initial value of 16 mm in five minutes, then what will be the amplitude after fifteen minutes?

1.  8 mm

2.  4 mm

3.  2 mm

4.  1 mm

Subtopic:  Damped Oscillations (OLD NCERT) |
 72%
From NCERT
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Which of the following is incorrect about simple harmonic oscillations of a particle? 

1. force and acceleration differ in phase by the angle of \(90^\circ.\) 
2. force varies linearly with displacement.
3. velocity is \(90^\circ\) ahead in phase relative to displacement from the mean position.
4. K.E. is zero at the extreme position(s).

Subtopic:  Energy of SHM |
 74%
From NCERT
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For a particle executing SHM, the graph between its momentum and displacement will be

1. Straight line

2. Hyperbola

3. Parabola

4. Ellipse

Subtopic:  Simple Harmonic Motion |
 58%
From NCERT
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A particle executes SHM of amplitude 10 m and period 4 s along a straight line. The velocity of the particle at a distance of 6 m from the mean position is: 

1.  2π m/s

2.  4π m/s 

3.  6π m/s

4.  5.4π m/s

Subtopic:  Simple Harmonic Motion |
 86%
From NCERT
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A uniform rod of mass m and length L pivoted from its one end is executing SHM with time period T. If rod suddenly breaks from the middle while passing through its mean position, then the time period of oscillation of remaining half part will be

1.  2T

2.  T2

3.  2T

4.  T2

Subtopic:  Angular SHM |
 66%
From NCERT
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A pendulum oscillates about its mean position \(\mathrm{C}.\) The position where the speed of the bob becomes maximum is: (ignore all dissipative forces)

                  

1. \(\mathrm{A}\) 2. \(\mathrm{B}\)
3. \(\mathrm{C}\) 4. \(\mathrm{D}\)
Subtopic:  Angular SHM |
 84%
From NCERT
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A particle executes linear SHM between \(x=A.\) The time taken to go from \(0\) to \(A/2\) is \(T_1\) and to go from \(A/2\) to \(A\) is \(T_2\) then:
1. \(T_1<T_2\) 2. \(T_1>T_2\)
3. \(T_1=T_2\) 4. \(T_1= 2T_2\)
Subtopic:  Linear SHM |
 72%
From NCERT
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The position x (in centimeter) of a simple harmonic oscillator varies with time t (in second) as x = 2cos0.5πt + π3The magnitude of the maximum acceleration of the particle in cm/s2 is:

1.  π/2

2.  π/4

3.  π2/2

4.  π2/4

Subtopic:  Simple Harmonic Motion |
 86%
From NCERT
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A horizontal platform is executing simple harmonic motion in the vertical direction with frequency f. A block of mass m is placed on the platform. What is the maximum amplitude of the SHM, so that the block is not detached from it?

1.  mg2π2f2

2.  mg4π2f2

2.  g2π2f2

4.  g4π2f2

Subtopic:  Simple Harmonic Motion |
 66%
From NCERT
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