Find equivalent resistance between \(X\) and \(Y\):
1. \(R\)
2. \(R/L\)
3. \(2R\)
4. \(5R\)
Vibrations of rope tied by two rigid ends shown by equation \(y=cos2\pi t\sin2\pi x,\) then the minimum length of the rope will be:
1. \(1\) m
2. \(\frac12\) m
3. \(5\) m
4. \(2\pi\) m
If we change the value of \(R,\) then:
1. voltage does not change on \(L\)
2. voltage does not change on \(LC\) combination
3. voltage does not change on \(C\)
4. voltage changes on \(LC\) combination
If \(V=ar\) where \(a\) is a constant and \(r\) is the distance, then the electric field at a point will be proportional to:
1. \(r\)
2. \(r^{-1}\)
3. \(r^{-2}\)
4. \(r^{0}\)
Electric field at point 20 cm away from the centre of a dielectric sphere is 100 V/m, the radius of the sphere is 10 cm, then the value of the electric field at a distance 3 cm from the centre is:
1. 100 V/m
2. 125 V/m
3. 120 V/m
4. 0
50 g ice at 0°C in insulator vessel, 50 g water of 100 °C is mixed in it, and then final temperature of the mixture is: (neglect the heat loss)
1. 10°C
2. 0°C << Tm < 20°C
3. 20°C
4. above 20°C
Real power consumption in a circuit is least when it contains:
1. High \(R\), low \(L\)
2. High \(R\), high \(L\)
3. Low \(R\), high \(L\)
4. High \(R\), low \(C\)
The linear density of a string is \(1.3\times 10^{-4}~\mathrm{kg/m}\) and the wave equation is \(y=0.021\sin(x+30t)\).
What is the tension in the string, where \(x\) is in meters and \(t\) in seconds?
1. \(
0.12 \mathrm{~N}
\)
2. \( 0.21 \mathrm{~N}
\)
3. \(1.2 \mathrm{~N}
\)
4. \( 0.012 \mathrm{~N}\)
Magnetic field at point O will be: (assume straight wire segments are infinite)
1. \(\frac{\mu_{_0}l}{2R}\) interior
2. \(\frac{\mu_{_0}l}{2R}\) exterior
3. \(\frac{\mu_{_0}l}{2R}1-\frac{l}{\pi}\) interior
4. \(\frac{\mu_{_0}l}{2R}1-\frac{l}{\pi}\) exterior
In Young's double-slit experiment, the spacing between two slits is \(0.1\) mm. If the screen is kept at \(1.0\) m from the slits and the wavelength of light is \(5000\) Å, then the fringe width is:
1. \(5\) cm
2. \(0.5\) m
3. \(1\) cm
4. \(0.5\) cm