| a. | \( \small{n=3, \ell=2, m=0, s=\frac{-1}{2} \,\& \ \,n=3, \ell=2, m=-1, s=\frac{+1}{2}}\) |
| b. | \(\small{n=2, \ell=1, m=1 , \ s=\frac{-1}{2}\, \&\, \ n=3, \ell=1, m=1 \mathrm{~s}=\frac{+1}{2}}\) |
| c. | \(\small{n=4, \ell=2, m=-1, s=\frac{1}{2}\, \&\, \ n=3, \ell=2, m=-1, s=\frac{1}{2}}\) |
| Column-I (Compound) | Column-II Hybridisation | ||
| (i) | \(PCl_5 \) | (a) | \(sp^3d^2 \) |
| (ii) | \([Pt(CN)_4]^{-2} \) | (b) | \(sp^3d \) |
| (iii) | \([Co(NH_3)_6]^{3+} \) | (c) | \(d^2sp^3 \) |
| (iv) | \(BrF_5 \) | (d) | \(dsp^2 \) |
| I | II | III | IV | |
| 1. | b | d | c | a |
| 2. | a | b | c | d |
| 3. | b | d | a | c |
| 4. | d | b | a | c |
| 1. | 8 | 2. | 6 |
| 3. | 10 | 4. | 7 |
| a. | \(B_2H_6 \) is Lewis acid. |
| b. | \(B_2H_6 \) has a planar structure. |
| c. | All B-H Bond lengths are equal in \(B_2H_6 \). |
| d. | In \(B_2H_6,\) four \(3C-2e^- \) bonds are present. |
| e. | \(B_2H_6 \) can be prepared by the reaction of \(BF_3 \) and \(NaBH_4 \). |
| 1. | a, b, c, d, e | 2. | a, e |
| 3. | a, b | 4. | d, e |
How many sp² carbon atoms are present in the product formed from the given reaction?

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