A satellite orbiting around Earth has potential energy \(E.\) Then the kinetic energy is:
1. \(-E/4\)
2. \(-E/3\)
3. \(-E/2\)
4. \(-E\)
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A geostationary satellite is orbiting the earth at a height of \(5R\) above the surface of the earth, \(R\) being the radius of the earth. The time period of another satellite in hours at a height of \(2R\) from the surface of the earth is:

1. \(5\)

2. \(10\)

3. \(6\sqrt2\)

4. \(\dfrac{6}{\sqrt{2}}\)

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AIPMT - 2012
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A satellite is in an elliptical orbit around a planet \(P\). It is observed that the velocity of the satellite when it is farthest from the planet is \(6\) times less than that when it is closest to the planet. The ratio of distances between the satellite and the planet at closest and farthest points is:
1. \(1:3\)
2. \(1:2\)
3. \(3:4\)
4. \(1:6\)

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A satellite of mass \(M\) is revolving around the Earth in a stationary orbit with a time period \(T.\) If \(10\%\) of the satellite's mass is detached, what will happen to its time period?
1. remain the same
2. increase by \(10\%\)
3. decrease by \(10\%\)
4. decrease by \(20\%\)

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For a satellite moving in an orbit around the earth, the ratio of kinetic energy to potential energy is:

1. \(\dfrac{1}{\sqrt{2}}\)

2. \(2\)

3. \(\sqrt{2} \)

4. \(\dfrac{1}{2}\)

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Consider a satellite orbiting the Earth in a circular orbit. Then:

1. The gravitational force on the satellite is the centripetal force.
2. The gravitational force on the satellite is the centrifugal force.
3. The gravitational force on the satellite is greater than the centripetal force.
4. All the above are true
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If the time period for one revolution by satellite near the Earth’s surface is \(T,\) then, the time period of revolution of the satellite at a height equal to the radius of the Earth will be:
1. \(\sqrt 8 ~T\) 2. \(\sqrt 2 ~T\)
3. \(\sqrt 4 ~T\) 4. \(\sqrt 3 ~T\)
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The energy required to shift a satellite from orbital radius \(r\) to orbital radius \(2r\) is \(E\). What energy will be required to shift the satellite from orbital radius \(2r\) to orbital radius \(3r\)?
1. \(E\)
2. \(E/2\)
3. \(E/3\)
4. \(E/4\)
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The correct formula for the height of a satellite from Earth's surface is:

1. \(\left(\dfrac{{T}^2 {R}^2 {g}}{4 \pi^2}\right)^{1 / 3}-{R} \)

2. \(\left(\dfrac{T^2 R^2 g}{4 \pi}\right)^{1 / 2}-R \)

3. \(\left(\dfrac{{T}^2 {R}^2}{4 \pi^2 {g}}\right)^{1 / 3}-{R}\)

4. \(\left(\dfrac{{T}^2 {R}^2 {g}}{4 \pi}\right)^{-1 / 3}+{R}\)
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A satellite which is geostationary in a particular orbit is taken to another orbit. Its distance from the centre of earth in new orbit is \(2\) times that of the earlier orbit. The time period in the second orbit is:
1. \(4.8\text{ hours}\)
2. \(48\sqrt2\text{ hours}\)
3. \(24\text{ hours}\)
4. \(24\sqrt2\text{ hours}\)

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