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Q. No.In the given circuit all resistances are of value of \(R ~\text{ohm}\) each. The equivalent resistance between \(A \) and \(B\) is:
1. \(\dfrac{5R}{2}\)
2. \(3R\)
3. \(\dfrac{5R}{3}\)
4. \(2R\)
Subtopic: Combination of Resistors |
Level 3: 35%-60%
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The figure shows three circuits \(\mathrm{I, II}\) and \(\mathrm{III}\) which are connected to a \(3~\text{V}\) battery. If the powers dissipated by the configurations \(\mathrm{I, II}\) and \(\mathrm{III}\) are \({P}_1,{P}_2\) and \({P}_3\) respectively, then:
1. \({P}_3>{P}_2>{P}_1 \)
2. \({P}_2>{P}_1>{P}_3 \)
3. \({P}_1>{P}_3>{P}_2\)
4. \({P}_1>{P}_2>{P}_3\)
1. \({P}_3>{P}_2>{P}_1 \)
2. \({P}_2>{P}_1>{P}_3 \)
3. \({P}_1>{P}_3>{P}_2\)
4. \({P}_1>{P}_2>{P}_3\)
Subtopic: Heating Effects of Current |
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Level 2: 60%+
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A uniform wire of length \(l\) and radius \({r}\) has a resistance of \(100~\Omega.\) It is recast into a wire of radius \(\frac{r}{2}.\) The resistance of the new wire will be:
1. \(400~\Omega\)
2. \(100~\Omega\)
3. \(200~\Omega\)
4. \(1600~\Omega\)
1. \(400~\Omega\)
2. \(100~\Omega\)
3. \(200~\Omega\)
4. \(1600~\Omega\)
Subtopic: Derivation of Ohm's Law |
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Level 2: 60%+
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A uniform metallic wire has a resistance of \(18 ~\Omega\) and is bent into an equilateral triangle. Then, the resistance between any two vertices of the triangle is:
1. \(4~\Omega\)
2. \(8~\Omega\)
3. \(12~\Omega\)
4. \(2~\Omega\)
1. \(4~\Omega\)
2. \(8~\Omega\)
3. \(12~\Omega\)
4. \(2~\Omega\)
Subtopic: Combination of Resistors |
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A conducting wire of length \(l\) area of cross-section \(A\) and electric resistivity \(\rho\) is connected between the terminals of a battery. A potential difference \(V\) is developed between its ends, causing an electric current. If the length of the wire of the same material is doubled and the area of the cross-section is halved, the resultant current would be:
1. \(\dfrac{4VA}{\rho l}\)
2. \(\dfrac{\rho l}{4VA}\)
3. \(\dfrac{3VA}{4\rho l}\)
4. \(\dfrac{VA}{4\rho l}\)
1. \(\dfrac{4VA}{\rho l}\)
2. \(\dfrac{\rho l}{4VA}\)
3. \(\dfrac{3VA}{4\rho l}\)
4. \(\dfrac{VA}{4\rho l}\)
Subtopic: Derivation of Ohm's Law |
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In the figure given below, the electric current flowing through the \(5~\text{k}\Omega\) resistor is:
1. \(3~\text{mA}\)
2. \(5~\text{mA}\)
3. \(7~\text{mA}\)
4. \(9~\text{mA}\)
1. \(3~\text{mA}\)
2. \(5~\text{mA}\)
3. \(7~\text{mA}\)
4. \(9~\text{mA}\)
Subtopic: Combination of Resistors |
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In the experimental setup of a metre bridge shown in the figure, the null point is initially obtained at a distance of \(40~\text{cm}\) from point \(A.\) When a \(10~\Omega\) resistor is connected in series with \({R_1,}\) the null point, shifts by \(10~\text{cm.}\) What resistance should be connected in parallel with \({(R_1+10)~\Omega}\) so that the null point returns to its initial position?
| 1. | \(20~\Omega\) | 2. | \(40~\Omega\) |
| 3. | \(60~\Omega\) | 4. | \(30~\Omega\) |
Subtopic: Meter Bridge |
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Level 3: 35%-60%
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In the given circuit the cells have zero internal resistance. The currents (in Amperes) passing through resistance \(R_1\) and \(R_2\) respectively, are:
1. \(1, 2\)
2. \(2, 2\)
3. \(0.5, 0\)
4. \(0, 1\)
1. \(1, 2\)
2. \(2, 2\)
3. \(0.5, 0\)
4. \(0, 1\)
Subtopic: Grouping of Cells |
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A \(2 ~\text{W }\)carbon resistor is color-coded with green, black, red, and brown respectively. The maximum current which can be passed through this resistor is:
1. \(20 ~\text{mA}\)
2. \(100~\text{mA}\)
3. \(0.4 ~\text{mA}\)
4. \(63 ~\text{mA}\)
1. \(20 ~\text{mA}\)
2. \(100~\text{mA}\)
3. \(0.4 ~\text{mA}\)
4. \(63 ~\text{mA}\)
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The Wheatstone bridge shown in the Figure, gets balanced when the carbon resistor is used as \(R_1\) has the colour code (Orange, Red, Brown). The resistors \( R_2\) and \(R_4\) are \(80 ~\Omega\) and \(40 ~\Omega,\) respectively. Assuming that the colour code for the carbon resistors gives their accurate values, the colour code for the carbon resistor, used as \(R_3\) would be:
1. Brown, Blue, Brown
2. Brown, Blue, Black
3. Red, Green, Brown
4. Grey, Black, Brown
1. Brown, Blue, Brown
2. Brown, Blue, Black
3. Red, Green, Brown
4. Grey, Black, Brown
Subtopic: Wheatstone Bridge |
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