In which of the following circuits the diode is reverse-biased?
(i)
(ii)
(iii)
(iv)
 
1. (ii) 2. (i) and (iv)
3. (iv) 4. (i)

Subtopic: Β PN junction |
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Level 1: 80%+
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In the circuit shown below, a \(\mathrm{Si}\) diode and a \(\mathrm{Ge}\) diode are connected in series with resistors of \(2.5~\text{k}\Omega\) and \(2.5~\text{k}\Omega,\) across a \(15 ~\text V\) supply. If the forward voltage drops of the \(\mathrm{Si}\) and \(\mathrm{Ge}\) diodes are \(0.7 ~\text V\) and \(0.3 ~\text V,\) respectively, what is the potential difference across the \(2.5~\text{k}\Omega\) resistor?

1. \(9.25~\text{V}\) 2. \(6.25~\text{V}\)
3. \(8.75~\text{V}\) 4. \(9.75~\text{V}\)
Subtopic: Β PN junction |
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Level 2: 60%+
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What is the current through the zener diode if its breakdown voltage is \(5~\text V?\)
 
1. \(58.33 ~\text{mA}\)
2. \(25 ~\text{mA}\)
3. \(28.33 ~\text{mA}\)
4. \(20.33 ~\text{mA}\)
Subtopic: Β Types of Semiconductors |
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In the voltage regulator circuit shown below, the reverse breakdown voltage of the Zener diode is \(3~\text{V}.\)Then the current through the Zener diode is:
         
1. \(7~\text{mA}\)
2. \(1.5~\text{mA}\)
3. \(5.5~\text{mA}\)
4. \(10~\text{mA}\)
Subtopic: Β Applications of PN junction |
Β 75%
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The truth table for the combination of logical gates
        
1. \(A\) \(B\) \(C\) 2. \(A\) \(B\) \(C\)
\(0\) \(0\) \(0\) \(0\) \(0\) \(0\)
\(0\) \(1\) \(0\) \(0\) \(1\) \(0\)
\(1\) \(0\) \(0\) \(1\) \(0\) \(1\)
\(1\) \(1\) \(1\) \(1\) \(1\) \(1\)
3. \(A\) \(B\) \(C\) 4. \(A\) \(B\) \(C\)
\(0\) \(0\) \(0\) \(0\) \(0\) \(0\)
\(0\) \(1\) \(1\) \(0\) \(1\) \(1\)
\(1\) \(0\) \(0\) \(1\) \(0\) \(0\)
\(1\) \(1\) \(1\) \(1\) \(1\) \(0\)
Subtopic: Β Logic gates |
Β 79%
Level 2: 60%+
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Which is the correct truth table for a given circuit?
1. \(A\) \(B\) \(Z\) 2. \(A\) \(B\) \(Z\)
\(0\) \(0\) \(1\) \(0\) \(0\) \(0\)
\(0\) \(1\) \(1\) \(0\) \(1\) \(1\)
\(1\) \(0\) \(1\) \(1\) \(0\) \(1\)
\(1\) \(1\) \(0\) \(1\) \(1\) \(0\)
3. \(A\) \(B\) \(Z\) 4. \(A\) \(B\) \(Z\)
\(0\) \(0\) \(0\) \(0\) \(0\) \(0\)
\(0\) \(1\) \(0\) \(0\) \(1\) \(1\)
\(1\) \(0\) \(0\) \(1\) \(0\) \(0\)
\(1\) \(1\) \(1\) \(1\) \(1\) \(1\)
Subtopic: Β Logic gates |
Β 75%
Level 2: 60%+
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In the voltage regulator circuit shown below, the reverse breakdown voltage of the Zener diode is \(5~\text{V}\) and power dissipated across it is \(100~\text{mW}.\) Then the value of unknown resistance \(R_S\) is:
  
1. \(43~\Omega\)
2. \(250~\Omega\)
3. \(1000~\Omega\)
4. \(1500~\Omega\)
Subtopic: Β Applications of PN junction |
Β 59%
Level 3: 35%-60%
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The logical circuit shown below is equivalent to:
 
1. NAND
2. NOR
3. AND
4. OR
Subtopic: Β Logic gates |
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A \(\mathrm{p\text-n}\) junction diode \((A)\) of the potential barrier \(3.8 ~\text V\) is connected with the Zener diode \((B)\) of a potential barrier \(1.2 ~\text V\) as shown in the figure. The length \(PR\) is \(20 ~\text{cm},\) then the maximum value of \(PQ\) (in \(\text{cm}\)) for which there is no current flow through the diode is:
 
1. \(5\)
2. \(8\)
3. \(2\)
4. \(3\)
Subtopic: Β Applications of PN junction |
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Level 3: 35%-60%
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 Draw the truth table of the given circuit.
1. \(A\) \(B\) \(X\) 2. \(A\) \(B\) \(X\)
\(0\) \(0\) \(0\) \(0\) \(0\) \(0\)
\(0\) \(1\) \(0\) \(0\) \(1\) \(0\)
\(1\) \(0\) \(0\) \(1\) \(0\) \(0\)
\(1\) \(1\) \(1\) \(1\) \(1\) \(0\)
3. \(A\) \(B\) \(X\) 4. \(A\) \(B\) \(X\)
\(0\) \(0\) \(1\) \(0\) \(0\) \(1\)
\(0\) \(1\) \(0\) \(0\) \(1\) \(0\)
\(1\) \(0\) \(0\) \(1\) \(0\) \(0\)
\(1\) \(1\) \(0\) \(1\) \(1\) \(1\)
Subtopic: Β Logic gates |
Β 92%
Level 1: 80%+
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