NCERT Exemplar (Objective) Based MCQs Nuclei Physics NEET Practice Questions, MCQs, Past Year Questions (PYQs), NCERT Questions, Question Bank, Class 11 and Class 12 Questions, and PDF solved with answers

Q1:

O_{2}

$\mathrm{O}_2$ molecule consists of two oxygen atoms. In the molecule, nuclear force between the nuclei of the two atoms:

1.	is not important because nuclear forces are short-ranged
2.	is as important as electrostatic force for binding the two atoms
3.	cancels the repulsive electrostatic force between the nuclei
4.	is not important because oxygen nucleus have equal number of neutrons and protons

Subtopic: Nuclear Binding Energy |

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Q2:

The gravitational force between

H -

$H\text-$ atom and another particle of mass

m

$m$ will be given by Newton's law

F = \frac{G M m}{r^{2}},

$F=\dfrac{GMm}{r^2},$ where

r

$r$ is in km and

1.	$M = m_{\text{proton}}+ m_{\text{electron}}.$
2.	$M = m_{\text{proton}}+ m_{\text{electron}}-\frac{B}{c^2}\left(B= 13.6~\text{eV}\right)$ .
3.	$M$ is not related to the mass of the hydrogen atom.
4.	$M = m_{\text{proton}}+ m_{\text{electron}}-\frac{\|V\|}{c^2}(\|V\|=$ magnitude of the potential energy of electron in the $H\text-$ atom).

Subtopic: Nuclear Binding Energy |

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Q3:

When a nucleus in an atom undergoes a radioactive decay, the electronic energy levels of the atom:

1.	do not change for any type of radioactivity
2.	change for $\alpha$ and $\beta\text-$ radioactivity but not for $\gamma\text-$ radioactivity
3.	change for $\alpha\text-$ radioactivity but not for others
4.	change for $\beta\text-$ radioactivity but not for others

Subtopic: Types of Decay |

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Q4:

Tritium is an isotope of hydrogen whose nucleus triton contains

2

$2$ neutrons and

1

$1$ proton. Free neutrons decay into

p + e^{- 1} + ν^{- 1} .

$p+e^{-1}+\nu^{-1}.$ If one of the neutrons in Triton decays, it would transform into

{H e}^{3}

$\mathrm{He}^{3}$ nucleus. This does not happen. This is because:

1.	triton energy is less than that of a $\mathrm{He}^{3}$ nucleus.
2.	the electron created in the beta decay process cannot remain in the nucleus.
3.	both the neutrons in Triton have to decay simultaneously resulting in a nucleus with $3$ protons, which is not a $\mathrm{He}^{3}.$ nucleus.
4.	free neutrons decay due to external perturbations which is absent in the Triton nucleus.

Subtopic: Types of Decay |

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Q5:

$M_x$ and $M_y$ denote the atomic masses of the parent and the daughter nuclei respectively in radioactive decay. The $Q\text -$ value for a $\beta^{-}$ decay is $Q_1$ and that for a $\beta^{+}$ decay is $Q_2.$ If $m_e$ denotes the mass of an electron, then which of the following statements is correct?

1.	$\small[Q_1=\left(M_x-M_y\right) c^2 \text { and } Q_2=\left[M_x-M_y-2 m_e\right] c^2$
2.	$\small[Q_1=\left(M_x-M_y\right) c^2 \text { and } Q_2=\left(M_x-M_y\right) c^2$
3.	$\small[Q_1=\left(M_x-M_y-2 m_e\right)c^2 \text { and } Q_2=\left(M_x-M_y+2 m_e\right) c^2$
4.	$\small[Q_1=\left(M_x-M_y+2 m_e\right) c^2 \text { and } Q_2=\left(M_x-M_y+2 m_e\right) c^4$

Subtopic: Nuclear Binding Energy |

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Q6:

In a nuclear reactor, moderators slow down the neutrons which come out in a fission process. The moderator used have light nuclei. The heavy nuclei will not serve the purpose, because:

1.	they will break up
2.	elastic collision of neutrons with heavy nuclei will not slow them down
3.	the net weight of the reactor would be unbearably high
4.	substances with heavy nuclei do not occur in the liquid or gaseous state at room temperature

Subtopic: Nuclear Energy |

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Q7:

Fusion processes, like combining two deuterons to form a

H e

$\mathrm{He}$ -nucleus are impossible at ordinary temperatures and pressure. The reasons for this can be traced to the fact:

(a)	nuclear forces have short-range.
(b)	nuclei are positively charged.
(c)	the original nuclei must be completely ionized before fusion can take place.
(d)	the original nuclei must first break up before combining with each other.

Choose the correct option:
1. (a), (c)
2. (a), (d)
3. (b), (d)
4. (a), (b)

Subtopic: Nuclear Energy |

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