- 1(current)
Q. No.
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly
A straight current-carrying wire carrying current \(I\) passes perpendicular to the plane of an imaginary rectangular loop \(PQRS\), passing through its centre \(O\) (into the diagram). The diagonals intersect at \(60^\circ,\) and side \(PS\) is smaller than side \(PQ. \) The value of \(\int \vec{B} \cdot d\vec{l} \) evaluated from \(P \) to \(Q \) (along \(PQ \)) has the magnitude:
| 1. | \(\dfrac{\mu_{0} I}{6}\) | 2. | \(\dfrac{2 \mu_{0} I}{6}\) |
| 3. | \(\dfrac{4\mu_{0} I}{6}\) | 4. | \(\dfrac{5\mu_{0} I}{6}\) |
Subtopic: Â Ampere Circuital Law |
 52%
Level 3: 35%-60%
Hints
From Ampere's circuital law, for a long straight wire of circular cross-section carrying a steady-current, the variation of the magnetic field inside and outside the region of the wire is:
| 1. | A linearly decreasing function of distance upto the boundary of the wire and then a linearly increasing one for the outside region. |
| 2. | Uniform and remains constant for both regions. |
| 3. | A linearly increasing function of distance upto the boundary of the wire and then a linearly decreasing one for the outside region. |
| 4. | A linearly increasing function of distance \(r\) upto the boundary of the wire and then decreasing one with \(1/r\) dependence for the outside region. |
Subtopic: Â Ampere Circuital Law |
 67%
Level 2: 60%+
NEET - 2022
Hints
- 1(current)
Q. No.
© 2026 GoodEd Technologies Pvt. Ltd.