| (A) | The charge stored in it increases. |
| (B) | The energy stored in it decreases. |
| (C) | Its capacitance increases. |
| (D) | The ratio of charge to its potential remains the same. |
| (E) | The product of charge and voltage increases. |
| 1. | (A), (C) and (E) only |
| 2. | (B), (D) and (E) only |
| 3. | (A), (B) and (C) only |
| 4. | (A), (B) and (E) only |
| 1. | \(15\) | 2. | \(7.5\) |
| 3. | \(0.3\) | 4. | \(150\) |

Two identical capacitors \(C_{1}\) and \(C_{2}\) of equal capacitance are connected as shown in the circuit. Terminals \(a\) and \(b\) of the key \(k\) are connected to charge capacitor \(C_{1}\) using a battery of emf \(V\) volt. Now disconnecting \(a\) and \(b\) terminals, terminals \(b\) and \(c\) are connected. Due to this, what will be the percentage loss of energy?
1. \(75\%\)
2. \(0\%\)
3. \(50\%\)
4. \(25\%\)
A parallel plate condenser has a uniform electric field \(E\)(V/m) in the space between the plates. If the distance between the plates is \(d\)(m) and area of each plate is \(A(\text{m}^2)\), the energy (joule) stored in the condenser is:
| 1. | \(\dfrac{1}{2}\varepsilon_0 E^2\) | 2. | \(\varepsilon_0 EAd\) |
| 3. | \(\dfrac{1}{2}\varepsilon_0 E^2Ad\) | 4. | \(\dfrac{E^2Ad}{\varepsilon_0}\) |