A particle of mass \(m\) is released from rest and follows a parabolic path as shown. Assuming that the displacement of the mass from the origin is small, which graph correctly depicts the position of the particle as a function of time?
           

1. 2.
3. 4.

Subtopic: Ā Energy of SHM |
Level 3: 35%-60%
AIPMT - 2011
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A mass of \(2.0\) kg is put on a flat pan attached to a vertical spring fixed on the ground as shown in the figure. The mass of the spring and the pan is negligible. When pressed slightly and released, the mass executes a simple harmonic motion. The spring constant is \(200\) N/m. What should be the minimum amplitude of the motion, so that the mass gets detached from the pan? 
(Take \(g=10\) m/s2
                

1. \(8.0\) cm
2. \(10.0\) cm
3. any value less than \(12.0\) cm
4. \(4.0\) cm
Subtopic: Ā Combination of Springs |
Ā 80%
Level 1: 80%+
AIPMT - 2007
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The radius of the circle, the period of revolution, initial position and direction of revolution are indicated in the figure.

The \(y\)-projection of the radius vector of rotating particle \(P\) will be:

1. \(y(t)=3 \cos \left(\dfrac{\pi \mathrm{t}}{2}\right)\), where \(y\) in m
2. \(y(t)=-3 \cos 2 \pi t\) , where \(y\) in m
3. \(y(t)=4 \sin \left(\dfrac{\pi t}{2}\right)\), where \(y\) in m
4. \(y(t)=3 \cos \left(\dfrac{3 \pi \mathrm{t}}{2}\right) \),  where \(y\) in m
Subtopic: Ā Phasor Diagram |
Ā 78%
Level 2: 60%+
NEET - 2019
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A spring of force constant \(k\) is cut into lengths of ratio \(1:2:3\). They are connected in series and the new force constant is \(k'\). Then they are connected in parallel and the force constant is \(k''\). Then \(k':k''\) is:
1. \(1:9\) 2. \(1:11\)
3. \(1:14\) 4. \(1:6\)
Subtopic: Ā Combination of Springs |
Ā 75%
Level 2: 60%+
NEET - 2017
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When a mass \(m\) is connected individually to two springs \(S_1\) and \(S_2,\) the oscillation frequencies are \(\nu_1\) and \(\nu_2.\) If the same mass is attached to the two springs as shown in the figure, the oscillation frequency would be: 

         

1. \(v_2+v_2\) 2. \(\sqrt{v_1^2+v_2^2}\)
3. \(\left(\dfrac{1}{v_1}+\dfrac{1}{v_1}\right)^{-1}\) 4. \(\sqrt{v_1^2-v_2^2}\)
Subtopic: Ā Combination of Springs |
Ā 73%
Level 2: 60%+
Hints

Two particles are oscillating along two close parallel straight lines side by side, with the same frequency and amplitudes. They pass each other, moving in opposite directions when their displacement is half of the amplitude. The mean positions of the two particles lie in a straight line perpendicular to the paths of the two particles. The phase difference is:
1. \(\frac{\pi}{6}\)
2. \(0\)
3. \(\frac{2\pi}{3}\)
4. \(\pi\)
Subtopic: Ā Linear SHM |
Ā 58%
Level 3: 35%-60%
AIPMT - 2011
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Two pendulums suspended from the same point have lengths of \(2\) m and \(0.5\) m. If they are displaced slightly and released, then they will be in the same phase when the small pendulum has completed:
1. \(2\) oscillations
2. \(4\) oscillations
3. \(3\) oscillations
4. \(5\) oscillations

Subtopic: Ā Simple Harmonic Motion |
Ā 69%
Level 2: 60%+
AIPMT - 1998
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If the time of mean position from amplitude (extreme) position is \(6\) seconds, then the frequency of SHM will be:
1. \(0.01~\text{Hz}\) 2. \(0.02~\text{Hz}\)
3. \(0.03~\text{Hz}\) 4. \(0.04~\text{Hz}\)
Subtopic: Ā Simple Harmonic Motion |
Ā 70%
Level 2: 60%+
AIPMT - 1998
Hints

A particle executing simple harmonic motion of amplitude \(5~\text{cm}\) has a maximum speed of \(31.4~\text{cm/s}.\) The frequency of its oscillation will be:
1. \(1~\text{Hz}\)
2. \(3~\text{Hz}\)
3. \(2~\text{Hz}\)
4. \(4~\text{Hz}\)

Subtopic: Ā Linear SHM |
Ā 88%
Level 1: 80%+
AIPMT - 2005
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The frequency of a simple pendulum in a free-falling lift will be:
1. zero
2. infinite
3. can't say
4. finite

Subtopic: Ā Angular SHM |
Ā 71%
Level 2: 60%+
AIPMT - 1999
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