A sample of \(0.1\) g of water at \(100^{\circ}\mathrm{C}\) and normal pressure (\(1.013 \times10^5\) N m–2) requires \(54\) cal of heat energy to convert it into steam at \(100^{\circ}\mathrm{C}\). If the volume of the steam produced is \(167.1\) cc, then the change in internal energy of the sample will be:

1. \(104.3\) J 2. \(208.7\) J
3. \(42.2\) J 4. \(84.5\) J
Subtopic:  First Law of Thermodynamics |
 70%
Level 2: 60%+
NEET - 2018
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