The potential energy function for a particle executing linear SHM is given by \(V \left(\right. x \left.\right) = \dfrac{1}{2} \left(kx\right)^{2}\) where k is the force constant of the oscillator (Fig). For k = 0.5 N/m, the graph of V(x) versus x is shown in the figure. A particle of total energy E turns back when it reaches \(x = \pm \left(x \right)_{m}\). If V and K indicate the PE and KE, respectively of the particle at \(x = + \left(x \right)_{m}\), then which of the following is correct?

1. V = 0, K = E
2. V = E, K = 0
3. V < E, K = 0
4. V = 0, K, E