Calculate the value of the dissociation constant for methanoic acid with a molar conductivity of 46.1 S cm² mol⁻¹ at 0.025 mol L⁻¹ concentration?
Given λ°(H⁺)= 349.6 S cm² mol⁻¹ and λ°(HCOO⁻) = 54.6 S cm² mol

1. \(1.27×10^{-4}~mol ~L^{−1}\)
2. \(5.17×10^{-5}~mol ~L^{−1}\)
3. \(3.67×10^{-4}~mol ~L^{−1}\)
4. \(4.87×10^{-5}~mol ~L^{−1}\)