A mixture of chloroform and acetone forms a solution with negative deviation from Raoult's law due to :
1. formation of hydrogen bonding between acetone and chloroform.
2. increase in the escaping tendency of molecules of each component.
3. stronger intermolecular forces between chloroform molecules than those between chloroform and acetone molecules.
4. repulsive forces.
Subtopic:  Raoult's Law |
 55%
Level 3: 35%-60%
NEET - 2026
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Consider the following statements about the solutions formed by mixing two liquids.
A. An ideal solution thus formed obeys Raoult's law throughout the composition range.
B. Mixture of chloroform and acetone shows negative deviation from Raoult's law.
C. Mixture of aniline and phenol shows positive deviation from Raoult's law.
 
1.  A and C only
2. A and B only
3. B and C only
4. A only
Subtopic:  Raoult's Law |
 65%
Level 2: 60%+
NEET - 2026
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Assertion (A): For an ideal solution formed by mixing liquids P and Q, \(\Delta_{mix} H = 0\) and \(\Delta_{mix} V = 0\)
Reason (R): No interactions occur between P and Q
In the light of the above statements, Choose the most appropriate answer from the options given below.  
1. (A) is not correct but (R) is correct 
2. Both (A)and (R) are correct and (R) is the correct explanation of (A)
3.  Both (A) and (R) are correct but (R) is NOT the correct explanation of (A) 
4. (A) is correct but (R) is not correct 
Subtopic:  Raoult's Law |
Level 3: 35%-60%
NEET - 2026
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Which of the following is true, when \(5\) moles of liquid \(\text X\) and \(10\) moles of liquid \(\text Y\) make a solution having a vapour pressure of \(70\) torr?
[Given: The vapour pressures of pure \(\text X\) and \(\text Y\) are \(63\) torr and \(78\) torr respectively]
1. The solution is ideal. 
2. The solution has a volume that is greater than the sum of individual volumes. 
3. The solution shows positive deviation. 
4. The solution shows negative deviation. 
Subtopic:  Raoult's Law |
 52%
Level 3: 35%-60%
NEET - 2025
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The correct option for the value of vapour pressure of a solution at 45 °C with benzene to octane in a molar ratio 3:2 is:

[At 45 °C vapour pressure of benzene is 280 mm Hg and that of octane is 420 mm Hg. Assume Ideal gas]

1. 336 mm of Hg 2. 350 mm of Hg
3. 160 mm of Hg 4. 168 mm of Hg
Subtopic:  Raoult's Law |
 77%
Level 2: 60%+
NEET - 2021
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The mixture that shows positive deviation from Raoult's law is:

1. Benzene + Toluene

2. Acetone + Chloroform

3. Chloroethane + Bromoethane

4. Ethanol + Acetone

Subtopic:  Raoult's Law |
 69%
Level 2: 60%+
NEET - 2020
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For an ideal solution, the correct option is:

1. mix G=0 at constant T and P

2. mix S=0 at constant T and P

3. mix V0 at constant T and P

4. mix H=0 at constant T and P

Subtopic:  Raoult's Law |
 83%
Level 1: 80%+
NEET - 2019
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The correct statement regarding a solution of two components A and B exhibiting positive deviation from ideal behaviour is :

1. Intermolecular attractive force between A-A and B-B are stronger than those between A-B
2. mixH = 0 at constant T and P
3. mixV = 0 at constant T and P
4. Intermolecular attractive forces between A-A and B-B are equal to those between A-B
Subtopic:  Raoult's Law |
 86%
Level 1: 80%+
NEET - 2019
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The incorrect statement among the following for an ideal solution is:

1. \(\Delta H_{\text{Mix}}=0\)
2. \(\Delta U_{\text{Mix}}=0\)
3. \(\Delta P=P_{\text{obs.}}-P_{\text{(Calculated by Raoult's law)}}=0\)
4. \(\Delta G_{\text{Mix}}=0\)
Subtopic:  Raoult's Law |
 81%
Level 1: 80%+
NEET - 2016
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Calculate the vapour pressure of a solution prepared by mixing 25.5 g of chloroform (CHCl₃) and 40 g of dichloromethane (CH₂Cl₂) at 25°C.

Given:
Vapour pressure of pure CHCl₃ = 200 mmHg
Vapour pressure of pure CH₂Cl₂ = 415 mmHg
Molar mass of CHCl₃ = 119.5 g mol⁻¹
Molar mass of CH₂Cl₂ = 85 g mol⁻¹

1. 90.40 mm Hg 2. 119.5 mm Hg 
3. 348 mm Hg  4. 173.9 mm Hg 
Subtopic:  Raoult's Law |
Level 4: Below 35%
AIPMT - 2012
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