Consider the following compounds,
A. n-Butane
B. 2-Methylbutane
C. n-Pentane
D. 2, 2-Dimethylpropane
The correct decreasing order of their boiling points is-
1. A>B>C>D
2. B>C>D>A
3. C>B>D>A
4. D>C>B>A
Which of the following will not show geometrical isomerism?
1. | 2. | ||
3. | 4. |
Match the hydrocarbons in Column I with the boiling points given in Column II.
A. n-pentane | 1. 282.5 K |
B. iso-pentane | 2. 309 K |
C. neo-pentane | 3. 301 K |
Codes
Options: | A | B | C |
1. | 2 | 3 | 1 |
2. | 1 | 2 | 3 |
3. | 2 | 1 | 3 |
4. | 3 | 2 | 1 |
Given below are two statements:
Assertion (A): | Among isomeric pentanes, 2,2-dimethylpropane has the highest boiling point. |
Reason (R): | Branching does not affect the boiling point. |
1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
3. | Both (A) and (R) are false. |
4. | (A) is true but (R) is false. |
The molecules having dipole moment are ________
a. 2,2-Dimethylpropane
b. trans-Pent-2-ene
c. cis-Hex-3-ene
d. 2,2,3,3 - Tetramethylbutane
Choose the correct option
1. (a, b)
2. (b, c)
3. (c, d)
4. (a, c)