In PO43- ion, the formal charge on the oxygen atom of the P-O bond is :

1. +1 2. –1
3. –0.75 4. +0.75

Subtopic:  Octate, Isoelectronic Species, Lewis Structure & Formal Charge |
 64%
Level 2: 60%+
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Which species lacks tetrahedral geometry?

1. BH4- 2. NH2-
3. CO32- 4. H3O+
Subtopic:  Hybridisation |
 64%
Level 2: 60%+
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The number of π bonds and σ bonds in the following structure is :

1. 6, 19 2. 4, 20
3. 5, 19 4. 5, 20
Subtopic:  Resonance & Nature of Compounds |
 86%
Level 1: 80%+
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The species that does not have unpaired electrons is:
 

1. \(N^+_2\) 2. \(O_2\)
3. \(O^{2-}_2\) 4. \(B_2\)
Subtopic:  M.O.T |
 73%
Level 2: 60%+
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If the electronic configuration of an element is 1s22s22p63s23p63d24s2, the four electrons that participate in the chemical bond formation will be from :

1. 3p6 2. 3p6,4s2
3. 3p6,3d2 4. 3d2,4s2
Subtopic:  Covalent Bond |
 87%
Level 1: 80%+
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The correct bond angle for \(\mathrm{sp}^2\) hybridization is:
1. \(90^\circ\)
2. \(120^\circ\)
3. \(180^\circ\)
4. \(109^\circ\)

Subtopic:  Hybridisation |
 89%
Level 1: 80%+
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The electronic configurations of the elements A, B, and C are given below.

A=1s22s22p6
B=1s22s22p63s23p3
C=1s22s22p63s23p5

The stable form of A may be represented by the formula:

1. A 2. A2
3. A3 4. A4
Subtopic:  Covalent Bond |
 82%
Level 1: 80%+
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The electronic configurations of the elements A, B, and C are given below.

A=1s22s22p6
B=1s22s22p63s23p3
C=1s22s22p63s23p5

The stable form of C may be represented by the formula : 

1. C 2. C2
3. C3 4. C4
 78%
Level 2: 60%+
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The electronic configurations of the elements A, B, and C are given below.

A=1s22s22p6
B=1s22s22p63s23p3
C=1s22s22p63s23p5

The bond between B and C will be : 

1. Ionic. 2. Covalent.
3. Hydrogen. 4. Coordinate.
Subtopic:  Covalent Bond |
 79%
Level 2: 60%+
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From the perspective of molecular orbital theory, which statement is false?

1. Be2 is not a stable molecule.
2. He2 is not stable but He2+ is expected to exist.
3. Bond strength of N2 is maximum amongst the homonuclear diatomic molecules belonging to the second period.
4. The order of energies of molecular orbitals in N2 molecule is: 

σ2s<σ2s*<σ2pz<(π2pxπ2py)
<(π2px*π2py*)<σ2pz*

Subtopic:  M.O.T |
 78%
Level 2: 60%+
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