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Q. No.The value of \(R\) in the given circuit when there is no current in the \(5 ~\Omega\) resistor is:
| 1. | \(12~\Omega\) | 2. | \(9~ \Omega\) |
| 3. | \(3~ \Omega\) | 4. | \(2~ \Omega\) |
Subtopic: Wheatstone Bridge |
87%
Level 1: 80%+
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The equivalent resistance \(R_{AB}\) between points \(A\) and \(B\) in the given network is:
| 1. | \(1R\) | 2. | \({\dfrac35}R\) |
| 3. | \({\dfrac78}R\) | 4. | \({\dfrac58}R\) |
Subtopic: Combination of Resistors |
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A battery with an EMF of \(10~\text V\) and an internal resistance of \(1~\Omega\) is connected to an external resistance of \(4~\Omega,\) as shown in the figure. The terminal voltage of the battery in this configuration is:
1. \(6~\text V\)
2. \(8~\text V\)
3. \(10~\text V\)
4. \(4~\text V\)
1. \(6~\text V\)
2. \(8~\text V\)
3. \(10~\text V\)
4. \(4~\text V\)
Subtopic: EMF & Terminal Voltage |
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A wire of length \('l'\) and resistance \(100 ~\Omega\) is divided into \(10\) equal parts. The first \(5\) parts are connected in series while the next \(5\) parts are connected in parallel. The two combinations are again connected in series. The resistance of this final combination is:
| 1. | \(52~ \Omega\) | 2. | \(55~ \Omega\) |
| 3. | \(60 ~\Omega\) | 4. | \(26~ \Omega\) |
Subtopic: Combination of Resistors |
68%
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There are two heaters \(A\) and \(B.\) The heater \(A\) takes time \(t_1\) to boil a given quantity of water, while \(B\) takes time \(t_2\) to boil the same quantity of water across the same supply voltage. If the two heaters are connected in series, the time taken by this combination to boil the same quantity of water will be:
| 1. | \(\large\dfrac{t_1t_2}{t_1+t_2}\) | 2. | \(t_1+t_2\) |
| 3. | \({\large\dfrac12}(t_1+t_2)\) | 4. | \(\large\dfrac{t_1t_2}{2(t_1+t_2)}\) |
Subtopic: Heating Effects of Current |
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Two heaters \(\mathrm{A}\) and \(\mathrm{B}\) have power rating of \(1~\text{kW}\) and \(2~\text{kW}\), respectively. Those two are first connected in series and then in parallel to a fixed power source. The ratio of power outputs for these two cases is:
1. \(2:9\)
2. \(1:2\)
3. \(2:3\)
4. \(1:1\)
1. \(2:9\)
2. \(1:2\)
3. \(2:3\)
4. \(1:1\)
Subtopic: Heating Effects of Current |
60%
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A wire of resistance \(R\) is cut into \(8\) equal pieces. From these pieces two equivalent resistance are made by adding four of these together in parallel. Then these two sets are added in series. The net effective resistance of the combination is:
| 1. | \(\dfrac{R}{16}\) | 2. | \(\dfrac{R}{8}\) |
| 3. | \(\dfrac{R}{64}\) | 4. | \(\dfrac{R}{32}\) |
Subtopic: Combination of Resistors |
57%
Level 3: 35%-60%
NEET - 2025
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Arrange the following in the order of their resistance.
Choose the correct answer from the options given below:
| A. | (\(0\) to \(1~\text A\)) ranged ammeter. |
| B. | (\(0\) to \(100~\text {mA}\)) ranged milli-ammeter. |
| C. | (\(0\) to \(500~\mu\text A\)) ranged micro-ammeter. |
| D. | (\(0\) to \(100~\text V\)) ranged voltmeter. |
Choose the correct answer from the options given below:
| 1. | \(\mathrm{A > B > C > D}\) | 2. | \(\mathrm{D > C > B > A}\) |
| 3. | \(\mathrm{D > A > B > C}\) | 4. | \(\mathrm{C > B > A > D}\) |
Subtopic: Derivation of Ohm's Law |
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The current passing through the battery in the given circuit, is:
1. \(2.5~\text{A}\)
2. \(1.5~\text{A}\)
3. \(2.0~\text{A}\)
4. \(0.5~\text{A}\)
1. \(2.5~\text{A}\)
2. \(1.5~\text{A}\)
3. \(2.0~\text{A}\)
4. \(0.5~\text{A}\)
Subtopic: Wheatstone Bridge |
Level 3: 35%-60%
NEET - 2025
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A constant voltage of \(50~\text{V}\) is maintained between the points \(A\) and \(B\) of the circuit shown in the figure. The current through the branch \(C D\) of the circuit is:
1. \(2.5~A\)
2. \(3.0~A\)
3. \(1.5~A\)
4. \(2.0~A\)
1. \(2.5~A\)
2. \(3.0~A\)
3. \(1.5~A\)
4. \(2.0~A\)
Subtopic: Kirchoff's Voltage Law |
Level 4: Below 35%
NEET - 2025
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