- 1(current)
Q. No.
| 1. | Only the right-sided deflection. |
| 2. | Only the left-sided deflection. |
| 3. | There will be no deflection irrespective of the position of the jockey. |
| 4. | Both right-sided and left-sided deflection and, at balance point, no deflection. |
In a meter bridge experiment, the null point is at a distance of \(30~\text{cm}\) from \(A.\) If a resistance of \(16~\Omega\) is connected in parallel with resistance \(Y\), the null point occurs at \(50~\text{cm}\) from \(A.\) The value of the resistance \(Y\) is:
| 1. | \(\dfrac{112}{3}~\Omega\) | 2. | \(\dfrac{40}{3}~\Omega\) |
| 3. | \(\dfrac{64}{3}~\Omega\) | 4. | \(\dfrac{48}{3}~\Omega\) |
A resistance wire connected in the left gap of a meter bridge balances a \(10~\Omega\) resistance in the right gap at a point which divides the bridge wire in the ratio \(3:2\). lf the length of the resistance wire is \(1.5~\text{m}\), then the length of \(1~\Omega\) of the resistance wire will be:
| 1. | \(1.0\times 10^{-1}~\text{m}\) | 2. | \(1.5\times 10^{-1}~\text{m}\) |
| 3. | \(1.5\times 10^{-2}~\text{m}\) | 4. | \(1.0\times 10^{-2}~\text{m}\) |
The metre bridge shown is in a balanced position with \(\frac{P}{Q} = \frac{l_1}{l_2}\). If we now interchange the position of the galvanometer and the cell, will the bridge work? If yes, what will be the balanced condition?
| 1. | Yes, \(\frac{P}{Q}=\frac{l_1-l_2}{l_1+l_2}\) | 2. | No, no null point |
| 3. | Yes, \(\frac{P}{Q}= \frac{l_2}{l_1}\) | 4. | Yes, \(\frac{P}{Q}= \frac{l_1}{l_2}\) |
- 1(current)
Q. No.
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