An ideal gas undergoes a cyclic transformation starting from the point A and coming back to the same point by tracing the path \(\mathrm{A} \rightarrow \mathrm{~B} \rightarrow \mathrm{C} \rightarrow \mathrm{D} \rightarrow \mathrm{~A}\) as shown in the three cases below:
Choose the correct option regarding change in internal energy, \(\Delta \mathrm{U} \):
1. \(\Delta \mathrm{U}\) (Case-III) > \(\Delta \mathrm{U}\) (Case-II) > \(\Delta \mathrm{U}\) (Case-I)
2. \(\Delta \mathrm{U}\) (Case-I) > \(\Delta \mathrm{U}\) (Case-II) > \(\Delta \mathrm{U}\) (Case-III)
3. \(\Delta \mathrm{U}\) (Case-I) > \(\Delta \mathrm{U}\) (Case-III) > \(\Delta \mathrm{U}\) (Case-II)
4. \(\Delta \mathrm{U}\) (Case-I) = \(\Delta \mathrm{U}\) (Case-II) = \(\Delta \mathrm{U}\) (Case-III)
Add Note
Subtopic: Â Thermodynamics' Properties and process |
 81%
Level 1: 80%+
Other Reason
Highlight in NCERT
Please attempt this question first.
Hints
Please attempt this question first.
Upgrade Your Plan
Upgrade now and unlock your full question bank experience with daily practice.