A compound X contains 32% of A, 20% of B and remaining percentage of C. Then, the empirical formula of X is :
(Given atomic mass of A = 64; B = 40; C = 32u)
1. ABC3
2. AB2C2
3. ABC4
4. A2BC2
Subtopic:  Empirical & Molecular Formula |
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From NCERT
NEET - 2024
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4.74 g of an inorganic compound contains 0.39g of K, 0.27 g Al, 1.92 g of \(\mathrm{SO_4}\) radicals and 2.16 g of water. If molar mass of the compound is \(948 \mathrm{~g} \mathrm{~mol}^{-1},\) the molecular formula of the inorganic compound is:
1. \(\mathrm{KAl}\left(\mathrm{SO}_4\right)_2 \cdot 12 \mathrm{H}_2 \mathrm{O}\)
2. \(\mathrm{K}_2 \mathrm{Al}_2\left(\mathrm{SO}_4\right)_6 \cdot 12 \mathrm{H}_2 \mathrm{O}\)
3. \(\mathrm{K}_2 \mathrm{SO}_4 \cdot \mathrm{Al}_2\left(\mathrm{SO}_4\right)_3 \cdot24 \mathrm{H}_2 \mathrm{O}\)
4. \(\mathrm{K}_2 \mathrm{SO}_6 \cdot \mathrm{Al}_2\left(\mathrm{SO}_4\right)_3 \cdot12 \mathrm{H}_2 \mathrm{O}\)
Subtopic:  Empirical & Molecular Formula |
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From NCERT
NEET - 2024
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Molar mass of a compound \(\text{(X)}\) whose \(2.6 \mathrm{~mol}\) weighs \(312 \mathrm{~g}\) is:

1. \(312 \mathrm{~g} \mathrm{~mol}^{-1}\)
2. \(120 \mathrm{~g} \mathrm{~mol}^{-1}\)
3. \(60 \mathrm{~g} \mathrm{~mol}^{-1}\)
4. \(811.2 \mathrm{~g} \mathrm{~mol}^{-1}\)
Subtopic:  Empirical & Molecular Formula |
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From NCERT
NEET - 2024
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An organic compound contains 80 % (by wt.) carbon and the remaining percentage of hydrogen. The empirical formula of this compound is:
[Atomic wt. of C is 12, H is 1] 

1. CH3 2. CH4
3. CH 4. CH2
Subtopic:  Empirical & Molecular Formula |
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From NCERT
NEET - 2021
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The percentages of C, H, and N in an organic compound are 40%, 13.3%, and 46.7% respectively.
The empirical formula of the compound is:

1. C3H13N3 2. CH2N
3. CH4N 4. CH6N
Subtopic:  Empirical & Molecular Formula |
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From NCERT
AIPMT - 2002
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A compound contains C, H, and O. If C = 40% and H = 6.67% and rest is oxygen, then the empirical formula of the compound will be:

1. CH2O

2. CH4O

3. CH4O2

4. CHO

Subtopic:  Empirical & Molecular Formula |
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From NCERT
AIPMT - 1999
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Percentage of C, H & N of a compound is given as follows:
C=40%, H=13.33%, N=46.67%
The empirical formula of the compound will be:

1. CH2N

2. C2H4N

3. CH4N

4. CH3N

Subtopic:  Empirical & Molecular Formula |
 76%
From NCERT
AIPMT - 1998
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