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Q. No.Five capacitors of capacitances;
\(C_1=C_2=C_3=C_4 = 10~\mu\text{F}\) and \(C_5 = 2.5~\mu\text{F}\) are connected as shown, along with a battery of \(50\) V.
The equivalent capacitance and the charges on each capacitor, respectively, are:
1. \(5~\mu\text{F}, 125~\mu\text{C}\) on all capacitors
2. \(5~\mu\text{F}, 250~\mu\text{C}\) on all capacitors
3. \(4~\mu\text{F}, 250~\mu\text{C}\) on \(C_1\) to \(C_4\) and \(125~\mu\text{C}\) on \(C_5\)
4. \(5~\mu\text{F}, 125~\mu\text{C}\) on \(C_1\) to \(C_4\) and \(25~\mu\text{C}\) on \(C_5\)
\(C_1=C_2=C_3=C_4 = 10~\mu\text{F}\) and \(C_5 = 2.5~\mu\text{F}\) are connected as shown, along with a battery of \(50\) V.
The equivalent capacitance and the charges on each capacitor, respectively, are:
1. \(5~\mu\text{F}, 125~\mu\text{C}\) on all capacitors
2. \(5~\mu\text{F}, 250~\mu\text{C}\) on all capacitors
3. \(4~\mu\text{F}, 250~\mu\text{C}\) on \(C_1\) to \(C_4\) and \(125~\mu\text{C}\) on \(C_5\)
4. \(5~\mu\text{F}, 125~\mu\text{C}\) on \(C_1\) to \(C_4\) and \(25~\mu\text{C}\) on \(C_5\)
Subtopic: Combination of Capacitors |
Level 3: 35%-60%
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Hints
Consider two uncharged capacitors of equal capacitance \(200~\text{pF}.\) One of them is charged by a \(100~\text{V}\) supply and disconnected. Now this capacitor is connected to the uncharged capacitor. The amount of electrostatic energy lost in the process is:
1. \(1.0\times 10^{-6}~\text{J}\)
2. \(0.5\times 10^{-6}~\text{J}\)
3. \(0.5~\text{J}\)
4. \(1.0~\text{J}\)
1. \(1.0\times 10^{-6}~\text{J}\)
2. \(0.5\times 10^{-6}~\text{J}\)
3. \(0.5~\text{J}\)
4. \(1.0~\text{J}\)
Subtopic: Energy stored in Capacitor |
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Level 3: 35%-60%
NEET - 2026
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Hints
Which of the following statements are correct?
Choose the correct answer from the options given below:
1. \(\mathrm{C,D~\text{and}~E}~\text{only}\)
2. \(\mathrm{A,B~\text{and}~D}~\text{only}\)
3. \(\mathrm{A,C~\text{and}~D}~\text{only}\)
4. \(\mathrm{A,C~\text{and}~E}~\text{only}\)
| \(\mathrm{A.}\) | Inside a conductor, the electrostatic field is zero. |
| \(\mathrm{B.}\) | The electric field at the surface of a charged conductor does not depend on its surface charge density. |
| \(\mathrm{C.}\) | The interior of a charged conductor can have no excess charge in the static situation. |
| \(\mathrm{D.}\) | At the surface of a charged conductor, the electrostatic field must be normal to the surface at every point. |
| \(\mathrm{E.}\) | The electrostatic potential is zero everywhere inside a charged conductor. |
1. \(\mathrm{C,D~\text{and}~E}~\text{only}\)
2. \(\mathrm{A,B~\text{and}~D}~\text{only}\)
3. \(\mathrm{A,C~\text{and}~D}~\text{only}\)
4. \(\mathrm{A,C~\text{and}~E}~\text{only}\)
Subtopic: Electrostatic Shielding |
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An electric dipole with dipole moment \(5\times10^{-6}~\text{C-m} \) is aligned with the direction of a uniform electric field of magnitude \(4\times10^{5}~\text{N/C}. \) The dipole is then rotated through an angle of \(60^\circ\) with respect to the electric field. The change in the potential energy of the dipole is:
| 1. | \(1.2~\text{J}\) | 2. | \(1.5~\text{J}\) |
| 3. | \(0.8~\text{J}\) | 4. | \(1.0~\text{J}\) |
Subtopic: Energy of Dipole in an External Field |
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NEET - 2025
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The plates of a parallel plate capacitor are separated by \(d.\) Two slabs of different dielectric constant \(K_1\) and \(K_2\) with thickness \(\dfrac{3}{8} d\) and \(\dfrac{d}{2},\) respectively are inserted in the capacitor. Due to this, the capacitance become two times larger than when there is nothing between the plates.
If \(K_1=1.25 ~K_2,\) the value of \(K_1\) is:
1. \(1.60\)
2. \(1.33\)
3. \(2.66\)
4. \(2.33\)
If \(K_1=1.25 ~K_2,\) the value of \(K_1\) is:
1. \(1.60\)
2. \(1.33\)
3. \(2.66\)
4. \(2.33\)
Subtopic: Dielectrics in Capacitors |
Level 3: 35%-60%
NEET - 2025
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Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
In the light of the above statements, choose the correct answer from the options given below:
| Assertion (A): | The potential \((V)\) at any axial point, at \(2~\text m\) distance (\(r\)) from the centre of the dipole of dipole moment vector \(\vec P\) of magnitude, \(4\times10^{-6}~\text{C m},\) is \(\pm9\times10^3~\text{V}.\) (Take \({\dfrac{1}{4\pi\varepsilon_0}}=9\times10^9\) SI units) |
| Reason (R): | \(V=\pm{\dfrac{2P}{4\pi\varepsilon_0r^2}},\) where \(r\) is the distance of any axial point situated at \(2~\text m\) from the centre of the dipole. |
| 1. | Both (A) and (R) are True and (R) is not the correct explanation of (A). |
| 2. | (A) is True but (R) is False. |
| 3. | (A) is False but (R) is True. |
| 4. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
Subtopic: Electric Potential |
56%
Level 3: 35%-60%
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Hints
In the following circuit, the equivalent capacitance between terminal \(A\) and terminal \(B\) is:
1. \(1~\mu\text F\)
2. \(0.5~\mu\text F\)
3. \(4~\mu\text F\)
4. \(2~\mu\text F\)
1. \(1~\mu\text F\)
2. \(0.5~\mu\text F\)
3. \(4~\mu\text F\)
4. \(2~\mu\text F\)
Subtopic: Combination of Capacitors |
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Hints
A thin spherical shell is charged by some source. The potential difference between the two points \(C\) and \(P\) (in V) shown in the figure is:
( Take \(\dfrac{1}{4 \pi \epsilon_0}=9 \times 10^9\) SI units)
( Take \(\dfrac{1}{4 \pi \epsilon_0}=9 \times 10^9\) SI units)
| 1. | \(1 \times 10^5\) | 2. | \(0.5 \times 10^5\) |
| 3. | \(\text{zero}\) | 4. | \(3 \times 10^5\) |
Subtopic: Electric Potential |
67%
Level 2: 60%+
NEET - 2024
Hints
If the plates of a parallel plate capacitor connected to a battery are moved closer to each other, then:
Choose the most appropriate answer from the options given below:
| (A) | The charge stored in it increases. |
| (B) | The energy stored in it decreases. |
| (C) | Its capacitance increases. |
| (D) | The ratio of charge to its potential remains the same. |
| (E) | The product of charge and voltage increases. |
| 1. | (A), (C) and (E) only |
| 2. | (B), (D) and (E) only |
| 3. | (A), (B) and (C) only |
| 4. | (A), (B) and (E) only |
Subtopic: Energy stored in Capacitor |
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Level 3: 35%-60%
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Hints
A dielectric slab of dielectric constant \(3\) having the same area of cross-section as that of a parallel plate capacitor but of thickness \({\frac{3}{4}}^{\text{th}}\) of the separation of the plates is inserted into the capacitor. The ratio of potential difference across the plates without dielectric to that with dielectric is:
| 1. | \(1:2\) | 2. | \(2:3\) |
| 3. | \(3:2\) | 4. | \(2:1\) |
Subtopic: Dielectrics in Capacitors |
56%
Level 3: 35%-60%
NEET - 2024
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