- 1(current)
Q. No.Twelve wires of equal resistance \(R\) are connected to form a cube. The effective resistance between two diagonal ends \(A\) and \(E\) will be:
| 1. | \(\dfrac{5 R}{6}\) | 2. | \(\dfrac{6 R}{5}\) |
| 3. | \(12 R\) | 4. | \(3 R\) |
Subtopic: Â Kirchoff's Voltage Law |
 71%
From NCERT
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The potential difference \(V_\mathrm{A}-V_\mathrm{B}\) between the points \(\mathrm{A}\) and \(\mathrm{B}\) in the given figure is:
| 1. | \(-3~\text{V}\) | 2. | \(+3~\text{V}\) |
| 3. | \(+6~\text{V}\) | 4. | \(+9~\text{V}\) |
Subtopic: Â Kirchoff's Voltage Law |
 78%
From NCERT
NEET - 2016
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The current through the \(5~\Omega\) resistor is:
| 1. | \(3.2\) A | 2. | \(2.8\) A |
| 3. | \(0.8\) A | 4. | \(0.2\) A |
Subtopic: Â Kirchoff's Voltage Law |
 68%
From NCERT
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The potential difference across \(8\) ohms resistance is \(48\) volts as shown in the figure below. The value of potential difference across \(X\) and \(Y\) points will be:
1. \(160\) volt
2. \(128\) volt
3. \(80\) volt
4. \(62\) volt
Subtopic: Â Kirchoff's Voltage Law |
 62%
From NCERT
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- 1(current)
Q. No.
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