For a wave \(y=y_0 \sin (\omega t-k x)\), for what value of \(\lambda\) is the maximum particle velocity equal to two times the wave velocity?
1. \(\pi y_0\)
2. \(2\pi y_0\)
3. \(\pi y_0/2\)
4. \(4\pi y_0\)

Subtopic:  Wave Motion |
 74%
From NCERT
AIPMT - 1998
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If the equation of a wave is represented by: \(y=10^{-4}~ \mathrm{sin}\left(100t-\dfrac{x}{10}\right)~\text m,\) where \(x \) is in meters and \(t\) in seconds, then the velocity of the wave will be:

1. \(100\) m/s 2. \(4\) m/s
3. \(1000\) m/s 4. \(0\) m/s
Subtopic:  Wave Motion |
 87%
From NCERT
AIPMT - 2001
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If a wave is travelling in a positive \(x\text-\)direction with \(A= 0.2~\text{m}\)\(v=360~\text{m/s}\), and \(\lambda= 60~\text{m}\), then the correct expression for the wave will be:
1.  \({y}=0.2 \sin \left[2 \pi\left(6{t}+\frac{x}{60}\right)\right]\)
2. \({y}=0.2 \sin \left[ \pi\left(6{t}+\frac{x}{60}\right)\right]\)
3. \({y}=0.2 \sin \left[2 \pi\left(6{t}-\frac{x}{60}\right)\right]\)
4. \(y=0.2 \sin \left[ \pi\left(6{t}-\frac{x}{60}\right)\right]\)
Subtopic:  Wave Motion |
 86%
From NCERT
AIPMT - 2002
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The phase difference between two waves, represented by
\(y_1= 10^{-6}\sin \left\{100t+\left(\frac{x}{50}\right) +0.5\right\}~\text{m}\)
\(y_2= 10^{-6}\cos \left\{100t+\left(\frac{x}{50}\right) \right\}~\text{m}\)
where \(x\) is expressed in metres and \(t\) is expressed in seconds, is approximate:
1. \(2.07\) radians
2. \(0.5\) radians
3. \(1.5\) radians
4. \(1.07\) radians

Subtopic:  Wave Motion |
 60%
From NCERT
AIPMT - 2004
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