A capacitor and a resistor are connected in series across the AC supply. Which of the following phasor diagrams may be correct?

1. 2.
3. 4.  

Subtopic:  Different Types of AC Circuits |
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In the transformer shown in the figure, the ratio of the number of turns of the primary to the secondary is \(\frac{N_1}{N_2}= \frac{1}{50}\). If a voltage source of \(10\) V is connected across the primary, then the induced current through the load of \(10~\text{k}\Omega\) in the secondary is:
          
1. \(\frac{1}{20}~\text{A}\)
2. zero
3. \(\frac{1}{10}~\text{A}\)
4. \(\frac{1}{5}~\text{A}\)
Subtopic:  Transformer |
 73%
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In the circuit shown, the value of RMS current is \(11\) A. The potential difference across the inductor is:

1. \(220\) V
2. zero
3. \(300\) V
4. \(200\) V
Subtopic:  Different Types of AC Circuits |
 67%
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In a heating arrangement, an alternating current having a peak value of \(28~\text{A}\) is used. To produce the same heat energy, if direct current is used to produce the same amount of heat, then its magnitude will be:
1. about \(14~\text{A}\)  2. about \(28~\text{A}\)
3. about \(20~\text{A}\) 4. cannot say
Subtopic:  AC vs DC |
 56%
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The AC source in the circuit shown in the figure produces a voltage \(V = 20\cos(2000t)\) volts. Neglecting source resistance, the voltmeter and ammeter readings will be (approximately):

1. \(4~\text{V}, 2.0~\text{A}\) 2. \(0~\text{V}, 2~\text{A}\)
3. \(5.6~\text{V}, 1.4~\text{A}\) 4. \(8~\text{V}, 2.0~\text{A}\)
Subtopic:  Different Types of AC Circuits |
 60%
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An AC ammeter is used to measure the current in a circuit. When a given direct current passes through the circuit, the AC ammeter reads \(6\) A. When another alternating current passes through the circuit, the AC ammeter reads \(8\) A. Then the reading of this ammeter if DC and AC flow through the circuit simultaneously is:
1. \(10 \sqrt{2}\) A
2. \(14\) A
3. \(10\) A
4. \(15\) A

Subtopic:  AC vs DC |
 65%
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If \(q\) is the capacitor's charge and \(i\) is the current at time \(t\), the voltage \(V\) will be:

1. \(L \frac{di}{dt}+{iR}-\frac{q}{C}=V\)
2. \(L \frac{di}{dt}-{iR}+\frac{q}{C}=V\)
3. \(L \frac{di}{dt}+{iR}+\frac{q}{C}=V\)
4. \(L\frac{di}{dt}-{iR}-\frac{q}{C}=V\)
Subtopic:  Different Types of AC Circuits |
 54%
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An \(LCR\) series circuit with \(100~\Omega\) resistance is connected to an AC source of \(200\) V and an angular frequency of \(300\) rad/s. When only the capacitance is removed, the current lags behind the voltage by \(60^{\circ}.\) When only the inductance is removed, the current leads the voltage by \(60^{\circ}.\) Calculate the power dissipated in the \(LCR\) circuit.
1. \(200\) W
2. \(400\) W
3. \(300\) W
4. zero

Subtopic:  Power factor |
 64%
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An ideal resistance \(R\), ideal inductance \(L\), ideal capacitance \(C\), and AC voltmeters \(V_1, V_2, V_3~\text{and}~V_4 \) are connected to an AC source as shown. At resonance:

         

1. Reading in \(V_3\) = Reading in \(V_1\)
2. Reading in \(V_1\) = Reading in \(V_2\)
3. Reading in \(V_2\) = Reading in \(V_4\)
4. Reading in \(V_2\) = Reading in \(V_3\)
Subtopic:  Different Types of AC Circuits |
 84%
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A transistor-oscillator using a resonant circuit with an inductance \(L\) (of negligible resistance) and a capacitance \(C\) has a frequency \(f\). If \(L\) is doubled and \(C\) is changed to \(4C\), the frequency will be:
1. \(\frac{f}{4}\)
2. \(8f\)
3. \(\frac{f}{2\sqrt{2}}\)
4. \(\frac{f}{2}\)

Subtopic:  Different Types of AC Circuits |
 86%
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