An ideal heat engine (Carnot engine) working between temperatures \(T_1\) and \(T_2\) has an efficiency \(\eta.\) The new efficiency if both the source and sink temperatures are doubled will be:
1. \(\frac{\eta}{2}\)
2. \(\eta\)
3. \(2\eta\)
4. \(3\eta\)
Subtopic:  Carnot Engine |
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The efficiency of an ideal heat engine is less than 100% because of:

1.  the presence of friction.
2.  the leakage of heat energy.
3.  unavailability of the sink at zero kelvin.
4.  All of these

Subtopic:  Carnot Engine |
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A Carnot engine whose sink is at \(300~\mathrm{K}\) has an efficiency of \(40\)%. By how much should the temperature of the source be increased to increase its efficiency by \(50\)% of its original efficiency?

1. \(275~\mathrm{K}\) 2. \(325~\mathrm{K}\)
3. \(250~\mathrm{K}\) 4. \(380~\mathrm{K}\)
Subtopic:  Carnot Engine |
 64%
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AIPMT - 2006
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