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Q. No.A particle is moving with a velocity \(\vec v=K(y \hat{i}+x\hat{j}),\) where \(K\) is a constant. The general equation for its path is:
1. \(y=x^2+\text{constant}\)
2. \(y^2=x+\text{constant}\)
3. \(y^2=x^2+\text{constant}\)
4. \(xy=\text{constant}\)
1. \(y=x^2+\text{constant}\)
2. \(y^2=x+\text{constant}\)
3. \(y^2=x^2+\text{constant}\)
4. \(xy=\text{constant}\)
Subtopic: Position & Displacement |
From NCERT
JEE
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Hints
Starting from the origin at time \(t=0\), with initial velocity \(5\hat{j}~\text{ms}^{-1}\), a particle moves in the x-y plane with a constant acceleration of \(\left(10\hat{i}+4\hat{j}\right)~\text{ms}^{-2}\). At time \(t\), its coordinates are (\(20\) m, \(y_0\) m). The values of \(t\) and \(y_0\) are, respectively.
1. \(4~\text{s}\) and \(52~\text{m}\)
2. \(5~\text{s}\) and \(25~\text{m}\)
3. \(2~\text{s}\) and \(18~\text{m}\)
4. \(2~\text{s}\) and \(24~\text{m}\)
Subtopic: Position & Displacement |
83%
From NCERT
JEE
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Hints
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A person moves from point \(A\) to point \(B\) along a circular path, as shown in the figure below. If the distance traveled by the person is \(60\) m, then the magnitude of displacement would be: (given that \(\cos135^\circ =-0.7\))
| 1. | \(42\) m | 2. | \(47\) m |
| 3. | \(19\) m | 4. | \(40\) m |
Subtopic: Position & Displacement |
From NCERT
JEE
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NEET 2026 - Target Batch - Vital
Hints
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NEET 2026 - Target Batch - Vital
A cyclist starts from the point P of a circular ground of radius \(2\) km and travels along its circumference to the point S. The displacement of a cyclist is –
1. \(4\) km
2. \(6\) km
3. \(\sqrt{8}\) km
4. \(8\) km
1. \(4\) km
2. \(6\) km
3. \(\sqrt{8}\) km
4. \(8\) km
Subtopic: Position & Displacement |
JEE
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Hints
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