Regardless of the specific technique used (GC, HPLC, TLC, etc.), what is the fundamental mechanism required for all chromatographic separations to occur?
1. Use of molecules that are soluble in water
2. Use of inert carrier gas
3. Calculation of Rf value for the molecule separated
4. Use of a mobile and a stationary phase
The number of σ and π bonds in the molecule are -
| 1. | 6 C – C sigma ( σ C - C ) bonds, 5 C–H sigma ( ( σ C - H ) bonds, and 3 C=C pi ( π C - C ) |
| 2. | 6 C – C sigma ( σ C - C ) bonds, 5 C–H sigma ( ( σ C - H ) bonds, and 2 C=C pi ( π C - C ) |
| 3. | 6 C – C sigma ( σ C - C ) bonds, 6 C–H sigma ( ( σ C - H ) bonds, and 3 C=C pi ( π C - C ) |
| 4. | 6 C – C sigma ( σ C - C ) bonds, 6 C–H sigma ( ( σ C - H ) bonds, and 2 C=C pi ( π C - C ) |
The number of σ and π bonds in the molecule are:
1. 7 = ( , 11 = , and 0= π
2. 6 = ( , 12 = , and 0= π
3. 12 = ( , 6 = , and 1= π
4. 5 = ( , 13 = , and 1= π
The number of σ and π bonds in the molecule are -
1. 2 = ( , 1= , and 1= π
2. 2 = ( , 2= , and 0= π
3. 2 = ( , 1= , and 1= π
4. 2 = ( , 1= , and 1= π
Chlorine atom can be classified as:
| 1. | Carbocation | 2. | Nucleophile |
| 3. | Electrophile | 4. | Carbanion |
The correct hybridization states of carbon atoms in the above compound are -
| 1. | C1= sp , C2= sp3 | 2. | C1= sp2 , C2= sp |
| 3. | C1= sp3 , C2= sp | 4. | C1= sp , C2= sp2 |
The correct hybridization states of carbon atoms marked as 1,2,3 in the following compound are:
\({ }^1 \mathrm{CH}_3-\mathrm{ }^2{C} \mathrm{H}={}^3{\mathrm{C}} \mathrm{H}_2 \)
| 1. | C1= sp , C2= sp3 , C3= sp2 | 2. | C1= sp2 , C2= sp3 , C3= sp3 |
| 3. | C1= sp3 , C2= sp2 , C3= sp2 | 4. | C1= sp3 , C2= sp3 , C3= sp3 |
The correct hybridization states of carbon atoms in the following compound are -
| 1. | C1= sp , C2= sp3 , C3= sp2 | 2. | C1= sp2 , C2= sp3 , C 3 = sp3 |
| 3. | C1= sp2 , C2= sp2 , C 3 = sp | 4. | C1= sp3 , C2= sp3 , C 3 = sp3 |
The correct hybridization states of carbon atoms in C6H6 (cyclic compound) is/are:
1. sp2
2. sp
3. sp3
4. All of the above
During estimation of nitrogen present in an organic compound, the ammonia evolved from 0.5 g of the compound in Kjeldahl’s estimation of nitrogen, neutralized 10 mL of 1 M H2SO4. The percentage of nitrogen in the compound is-
1. 46.0 %
2. 51.0%
3. 56.0%
4. 49.0%