Q. No.Z in the below reaction sequence will be:
\(CH_3CH_2Cl \)\(\xrightarrow[]{NaCN}\ X\ \)\(\xrightarrow[]{Ni/H_2}\ Y \ \)\(\xrightarrow{Ac_2O}\ Z\)
1. \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{NHCOCH}_3
\)
2. \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{NH}_2
\)
3. \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CONHCH}_3
\)
4. \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CONHCOCH}_3\)
\(CH_3CH_2Cl \)\(\xrightarrow[]{NaCN}\ X\ \)\(\xrightarrow[]{Ni/H_2}\ Y \ \)\(\xrightarrow{Ac_2O}\ Z\)
1. \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{NHCOCH}_3 \)
2. \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{NH}_2 \)
3. \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CONHCH}_3 \)
4. \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CONHCOCH}_3\)
The product B in the below mentioned reaction is:
\(Acetamide \overset{P_2O_5}{\longrightarrow}A\ \overset{4H}{\longrightarrow}\ B\)
1. CH3NH2
2. C2H5NH2
3. CH3CN
4. CH3COONH4
Which of the following compounds, when reduced with lithium aluminium hydride, produces a secondary amine?
1. Nitroethane
2. Methylisocyanide
3. Acetamide
4. Methyl cyanide
Benzene diazonium chloride on reaction with aniline in the presence of dilute hydrochloric acid gives:
| 1. |  |
2. |  |
| 3. |  |
4. |  |
Based on the statements given, which option is correct?
| Assertion (A): | Nitration of aniline at a low temperature gives 47% m-nitroaniline. |
| Reason (R): | In acidic medium, group is converted into group which is m-directing. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | Both (A) and (R) are False. |
Select the correct option based on statements below:
| Assertion (A): | C6H5NH2 is a 1° amine and can be prepared by Gabriel phthalimide synthesis. |
| Reason (R): | C6H5NH2 is strongly basic in nature. |
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | Both (A) and (R) are false. |
Select the correct option based on statements below:
| Assertion (A): | of aniline is higher than ethylamine. |
| Reason (R): | The lone pair of group in aniline is involved in conjugation with a benzene ring. |
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | Both (A) and (R) are false. |
Aniline undergoes the following reaction sequence to yield product D:
What is the formula of the product D?
1.
2.
3.
4.
In a set of reactions, propanoic acid yielded a compound (D).
\(CH_3CH_2COOH\ \text{(A)} \xrightarrow[]{SOCl_2}\ \text{(B)} \)
\(\ \xrightarrow[]{NH_3}\ \text{(C)}\ \xrightarrow[Br_2]{KOH}\ \text{(D)}\)
The formula for (D) is:
1.
2.
3.
4.
CH3CH2CO-NH2 can be converted into CH3CH2NH2 in the presence of:
1. LiAlH4
2. H2/Pt
3. Sn/HCl
4. NaOBr/OH–
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