The maximum number of neutrons are present in the nuclei of
The complete symbol for the atom with the given atomic number (Z) and atomic mass (A) would be, respectively :
i. | Z = 17 , A = 35. |
ii. | Z = 92 , A = 233. |
iii. | Z = 4 , A = 9. |
1.
2.
3.
4.
Yellow light emitted from a sodium lamp has a wavelength (λ) of 580 nm.
The frequency (ν) and wave number of this yellow light would be, respectively:
1. 517 x 1014 s-1 , 172 x 106 m-1
2. 6.17 x 1014 s-1 , 1.72 x 106 m-1
3. 4.17 x 1014 s-1 , 2.72 x 106 m-1
4. 5.17 x 1014 s-1 , 1.72 x 106 m-1
The energy of the photon with a frequency of 3×1015 Hz is :
1. 1.988 × J
2. 1.588 × J
3. 1.288 × J
4. 2.988 × J
A photon of wavelength 4 × 10–7 m strikes a metal surface, the work function of the metal being 2.13 eV. The kinetic energy of emission would be:
1. | 0.97 eV | 2. | 97 eV |
3. | 4.97 × eV | 4. | 5.84 × 105 eV |
The wavelength of the light emitted when the electron returns to the ground state in the H atom, from n = 5 to n = 1, would be: (The ground-state electron energy is –2.18 × 10-18 j)
1. Wavelength = 9.498 x 10-8 km
2. Wavelength = 12.498 x 10-8 m
3. Wavelength = 9.498 x 10-8 m
4. Wavelength = 9.498 x 10-8 cm
The possible values of n, l, and m for the electron present in 3d would be respectively:
1. n = 3, l = 1, m = – 2, – 1, 3, 1, 2
2. n = 3, l = 3, m = – 2, – 1, 0, 1, 2
3. n = 3, l = 2, m = – 2, – 1, 0, 1, 2
4. n = 5, l = 2, m = – 2, – 1, 0, 1, 2
The number of electrons in the species , are respectively:
1. 15, 2, 1
2. 15, 1, 2
3. 1, 2, 15
4. 2, 1, 15
Orbital that does not exist:
1. | 6p | 2. | 2s |
3. | 3f | 4. | 2p |
The set of quantum numbers which represent 3p is :
1. n =1, l =0;
2, n = 3; l=1
3. n = 4; l =2;
4. n = 4; l = 3