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Q. No.A parallel plate capacitor made of circular plates is being charged such that the surface charge density on its plates is increasing at a constant rate with time. The magnetic field arising due to displacement current is:
| 1. | non-zero everywhere with maximum at the imaginary cylindrical surface connecting peripheries of the plates |
| 2. | zero between the plates and non-zero outside |
| 3. | zero at all places |
| 4. | constant between the plates and zero outside the plates |
Subtopic: Displacement Current |
From NCERT
NEET - 2025
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The electric field in a plane electromagnetic wave is given by \(E_z=60\cos(5x+1.5\times10^9t)~\text{V/m}.\) Then expression for the corresponding magnetic field is (here subscripts denote the direction of the field):
| 1. | \(B_z=60\cos(5x+1.5\times10^9t)~\text T\) |
| 2. | \(B_y=60\sin(5x+1.5\times10^9t)~\text T\) |
| 3. | \(B_y=2\times10^{-7}\cos(5x+1.5\times10^9t)~\text T\) |
| 4. | \(B_x=2\times10^{-7}\cos(5x+1.5\times10^9t)~\text T\) |
Subtopic: Properties of EM Waves |
61%
From NCERT
NEET - 2025
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A parallel plate capacitor is charged by connecting it to a battery through a resistor. If \(i\) is the current in the circuit, then in the gap between the plates:
| 1. | A displacement current of magnitude equal to \(i\) flows in the same direction as \(i.\) |
| 2. | A displacement current of magnitude equal to \(i\) flows in the opposite direction to \(i.\) |
| 3. | A displacement current of magnitude greater than \(i\) flows but it can be in any direction. |
| 4. | There is no current. |
Subtopic: Displacement Current |
62%
From NCERT
NEET - 2024
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The property which is not of an electromagnetic wave travelling in free space is that:
| 1. | the energy density in electric field is equal to energy density in magnetic field. |
| 2. | they travel with a speed equal to \(\dfrac{1}{\sqrt{\mu_0~ \varepsilon_0}} .\) |
| 3. | they originate from charges moving with uniform speed. |
| 4. | they are transverse in nature. |
Subtopic: Properties of EM Waves |
68%
From NCERT
NEET - 2024
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If \(\vec{E}\) and \(\vec{B}\) represent the electric field vector and magnetic field vector, respectively, in an electromagnetic wave then the direction of EM wave is along:
| 1. | \(\vec{E}\) | 2. | \(\vec{B}\) |
| 3. | \(\vec{E}\times\vec{B}\) | 4. | \(\vec{B}\times\vec{E}\) |
Subtopic: Properties of EM Waves |
92%
From NCERT
NEET - 2024
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Match List-I with List-II (the symbols carry their usual meaning).
Choose the correct answer from the options given below:
| List-I | List-II | ||
| A. | \( \oint \vec{E} \cdot d \vec{A}=\dfrac{Q}{\varepsilon_0}\) | I. | Ampere-Maxwell's law |
| B. | \( \oint \vec{B} \cdot d \vec{A}=0 \) | II. | Faraday's law |
| C. | \( \oint \vec{E} \cdot d\vec{ l}=\dfrac{-d(\phi)}{d t} \) | III. | Gauss's law of electrostatics |
| D. | \( \oint \vec{B} \cdot d\vec{l}=\mu_0 i_c+ \mu_0 \varepsilon_0 \dfrac{d\left(\phi_E\right)}{d t}\) | IV. | Gauss's law of magnetism |
| 1. | A-III, B-IV, C-II, D-I | 2. | A-IV, B-III, C-II, D-I |
| 3. | A-III, B-II, C-IV, D-I | 4. | A-IV, B-I, C-III, D-II |
Subtopic: Maxwell's Equations |
83%
From NCERT
NEET - 2024
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Among the various types of electromagnetic radiation, the one with the smallest wavelength is:
| 1. | \(\mathrm{X}\)-rays | 2. | Gamma rays |
| 3. | Ultraviolet rays | 4. | Microwaves |
Subtopic: Electromagnetic Spectrum |
80%
From NCERT
NEET - 2024
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If the ratio of relative permeability and relative permittivity of a uniform medium is \(1 : 4.\) The ratio of the magnitudes of electric field intensity \((E)\) to the magnetic field intensity \((H)\) of an EM wave propagating in that medium is:
\(\left(\text{Given that}\sqrt{\frac{\mu_0}{\varepsilon_0}}=120\pi\right)\)
1. \(30\pi:1\)
2. \(1:120\pi\)
3. \(60\pi:1\)
4. \(120\pi:1\)
\(\left(\text{Given that}\sqrt{\frac{\mu_0}{\varepsilon_0}}=120\pi\right)\)
1. \(30\pi:1\)
2. \(1:120\pi\)
3. \(60\pi:1\)
4. \(120\pi:1\)
Subtopic: Properties of EM Waves |
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NEET - 2024
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In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of \(2.0\times 10^{10}~ \text{Hz}\) and amplitude \(48~\text{Vm}^{-1}\). Then the amplitude of the oscillating magnetic field is: (Speed of light in free space \(3\times 10^{8}~ \text{ms}^{-1}\))
1. \(1.6 \times 10^{-6} ~\text{T}\)
2. \(1.6 \times 10^{-9} ~\text{T}\)
3. \(1.6 \times 10^{-8} ~\text{T}\)
4. \(1.6 \times 10^{-7} ~\text{T}\)
1. \(1.6 \times 10^{-6} ~\text{T}\)
2. \(1.6 \times 10^{-9} ~\text{T}\)
3. \(1.6 \times 10^{-8} ~\text{T}\)
4. \(1.6 \times 10^{-7} ~\text{T}\)
Subtopic: Properties of EM Waves |
64%
From NCERT
NEET - 2023
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\(\varepsilon_0\) and \(\mu_0\) are the electric permittivity and magnetic permeability of free space respectively. If the corresponding quantities of a medium are \(2\varepsilon_0\) and \(1.5\mu_0\) respectively, the refractive index of the medium will nearly be:
1. \(\sqrt2\)
2. \(\sqrt3\)
3. \(3\)
4. \(2\)
1. \(\sqrt2\)
2. \(\sqrt3\)
3. \(3\)
4. \(2\)
Subtopic: Properties of EM Waves |
81%
From NCERT
NEET - 2023
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