A ball is thrown upward with an initial velocity \(v_0\) from the surface of the earth. The motion of the ball is affected by a drag force equal to \(myv^2\) (where \(m\) is mass of the ball, \(v\) is its instantaneous velocity and \(y\) is a constant). The time taken by the ball to rise to its zenith (maximum height) is:
1. \( \frac{1}{\sqrt{y g}} \tan ^{-1}\left(\sqrt{\frac{y}{g} v_0}\right) \)
2. \( \frac{1}{\sqrt{2 y g}} \tan ^{-1}\left(\sqrt{\frac{2 y}{g} v_0}\right) \)
3. \( \frac{1}{\sqrt{y g}} \sin ^{-1}\left(\sqrt{\frac{y}{g}} v_0\right) \)
4. \( \frac{1}{\sqrt{y g}}\ln\left(1+\sqrt{\frac{y}{g} v_0}\right)\)

Subtopic:  Non Uniform Acceleration |
From NCERT
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A block of mass \(2\) kg moving on a horizontal surface with a speed of \(4\) ms-1 enters a rough surface ranging from \(x=0.5\) m to \(x=1.5\) m. The retarding force in this range of rough surface is related to distance by \(F = -kx\) where \(k=12\) Nm-1. The speed of the block as it just crosses the rough surface will be:
1. zero
2. \(1.5\) ms-1
3. \(2.0\) ms-1
4. \(2.5\) ms-1
Subtopic:  Non Uniform Acceleration |
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From NCERT
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Two cars are travelling towards each other at speed of \(20\) ms-1 each. When the cars are 300 m apart, both the drivers apply brakes and the cars retard at the rate of \(2\) ms-2. The distance between them when they come to rest is :
1. \(200\) m
2. \(50\) m
3. \(100\) m
4. \(25\) m
Subtopic:  Non Uniform Acceleration |
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