Assume that an electric field \(\vec{E}=30x^2\hat{i}\) exists in space. Then the potential difference \(V_A-V_O\), where \(V_O\) is the potential at the original and \(V_A\) the potential at \(x=2~\text{m}\) is:
1. \(-120~\text{V}\)
2. \(-80~\text{V}\)
3. \(80~\text{V}\)
4. \(120~\text{V}\)

Subtopic:  Relation between Field & Potential |
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A parallel plate capacitor is made of two circular plates separated by a distance of \(5~\text{mm}\) and with a dielectric of dielectric constant \(2.2\) between them. When the electric field in the dielectric is \(3\times 10^4~\text{V/m}\), the charge density of the positive plate will be close to:
1. \( 3 \times 10^{-7} ~\text{C} / \text{m}^2 \)
2. \( 3 \times 10^4~\text{C} / \text{m}^2 \)
3. \( 6 \times 10^4 ~\text{C} / \text{m}^2 \)
4. \( 6 \times 10^{-7}~\text{C} / \text{m}^2 \)

Subtopic:  Capacitance |
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A uniformly charged solid sphere of radius \(R\) has potential \(V_0\) (measured with respect to \(\infty\)) on its surface. For this sphere, the equipotential surfaces with potentials \(\frac{3V_0}{2},\frac{5V_0}{4},\frac{3V_0}{4}\) and \(\frac{V_0}{4}\) have radius \(R_1,R_2,R_3\) and \(R_4\) respectively. then:

1. \({R}_1=0 \text { and } {R}_2>\left({R}_4-{R}_3\right) \)
2. \({R}_1 \neq 0 \text { and }\left({R}_2-{R}_1\right)>\left({R}_4-{R}_3\right) \)
3. \({R}_1=0 \text { and } {R}_2<\left({R}_4-{R}_3\right) \)
4. \(2 {R}<{R}_4\)
Subtopic:  Electric Potential |
From NCERT
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In the given circuit, charge \(Q_2\) on the \(2~\mu\text{F}\) capacitor changes as \(C\) is varied from \(1~\mu\text{F}\) to \(3~\mu\text{F}\)\(Q_2\) as a function of '\(C\)' is given properly by: (figures are drawn schematically and are not to scale)

           

1. 2.
3.   4.  
Subtopic:  Capacitance |
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The figure shows two point charges \(+{Q}\) and \(– {Q}\) inside the cavity of a spherical shell. The charges are kept near the surface of the cavity on opposite sides of the centre of the shell. If \(\sigma _1\) is the surface charge on the inner surface and \({Q}_1\) net charge on it and \(\sigma _1\) the surface charge on the outer surface and \({Q}_2\) net charge on it then:

 
1. \(\begin{aligned} & \sigma_1 \neq 0, Q_1=0, ~~\text{and}~~\sigma_2 \neq 0, Q_2=0 \end{aligned}\)
2. \(\begin{aligned} & \sigma_1=0, Q_1=0,~~\text{and}~~ \sigma_2=0, Q_2=0 \end{aligned}\)
3. \(\begin{aligned} \sigma_1 & \neq 0, Q_1 \neq 0,~~\text{and}~~ \sigma_2 \neq 0, Q_2 \neq 0 \end{aligned}\)
4. \(\begin{aligned} & \sigma_1 \neq 0, Q_1=0, ~~\text{and}~~\sigma_2=0, Q_2=0 \end{aligned}\)
 
Subtopic:  Electrostatic Shielding |
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The figure shows a system of four capacitors connected across a \(10~\text{V}\) battery. The charge that will flow from the switch \({S}\) when it is closed is: 
 
1. \(5~\mu\text{C}\) from \({b}\) to \({a}\)
2. \({20}~\mu\text{C}\) from \({a}\) to \({b}\)
3. zero
4. \(5~\mu\text{C}\) from \({a}\) to \({b}\)
Subtopic:  Capacitance |
From NCERT
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An electric field \({\vec{E}=(25\hat{i}+30\hat{j})~\text{NC}^{-1}}\) exists in a region of space. If the potential at the origin is taken to be zero then the potential at \({x=2}~\text{m},\) \({y=2}~\text{m}\) is:
1. \({-110}~\text{J}\)
2. \({-140}~\text{J}\)
3. \({-120}~\text{J}\)
4. \({-130}~\text{J}\)
Subtopic:  Relation between Field & Potential |
From NCERT
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A combination of capacitors is set up as shown in the figure. The magnitude of the electric field, due to a point charge \(Q\) (having a charge equal to the sum of the charges on the \(4~\mu \text{F}\) and \(9~\mu\text{F}\) capacitors), at a point distant \(30~\text{m}\) from it, would equal:
                                       
1. \(240~\text{N/C}\)
2. \(360~\text{N/C}\)
3. \(420~\text{N/C}\)
4. \(480~\text{N/C}\)

Subtopic:  Capacitance |
From NCERT
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Three capacitors each of \({4}~\mu \text{F}\) are to be connected in such a way that the effective capacitance is \({6}~\mu \text{F}.\) This can be done by connecting them:
1. connecting all of them in a series
2. connecting all of them in parallel
3. connecting two in series and one in parallel
4. connecting two in parallel and one in series
Subtopic:  Combination of Capacitors |
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A capacitance of \(2~\mu\text{F}\) is required in an electrical circuit across a potential difference of \(1.0~\text{kV}\). A large number of \(1~\mu\text{F}\) capacitors are available which can withstand a potential difference of not more than \(300~\text{V}\). The minimum number of capacitors required to achieve this is:
1. \(2\)
2. \(16\)
3. \(24\)
4. \(32\)

Subtopic:  Capacitance |
From NCERT
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