An alternating voltage \(V(t)=220 \sin 100 \pi t~\text{volts}\) is applied to a purely resistive load of \(50~\mathrm{\Omega}.\) The time taken for the current to rise from half of the peak value to the peak value is:
1. \(5~\text{ms}\)
2. \(7.2~\text{ms}\)
3. \(3.3~\text{ms}\)
4. \(2.2~\text{ms}\)

Subtopic:  AC vs DC |
 62%
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