This action cannot be undone. This will permanently delete All Practiced Questions.
Only bookmarked questions of selected question set or default questions are shown here. Click Here to view all bookmarked questions of the chapter
An alternating voltage \(V(t)=220 \sin 100 \pi t~\text{volts}\) is applied to a purely resistive load of \(50~\mathrm{\Omega}.\) The time taken for the current to rise from half of the peak value to the peak value is:
1. \(5~\text{ms}\)
2. \(7.2~\text{ms}\)
3. \(3.3~\text{ms}\)
4. \(2.2~\text{ms}\)
Other Reason
© 2025 GoodEd Technologies Pvt. Ltd.