A short bar magnet is placed in the magnetic meridian of the earth with the north pole pointing north. Neutral points are found at a distance of \(30 ~\text{cm}\) from the magnet on the East-West line, drawn through the middle point of the magnet. The magnetic moment of the magnet in \(\text{Am}^{2}\) is close to:
(Given \({\mu_0\over 4\pi}=10^{-7}\) in \(\text{S.I.}\) units and \({B_H}=\) Horizontal component of earth's magnetic field \(=3.6\times10^{-5}\) Tesla)
1. \(14.6\)
2. \(19.4\)
3. \(9.7\)
4. \(4.9\)
Subtopic:  Magnetic Moment |
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The dipole moment of a circular loop carrying a current \(I\), is \(m\) and the magnetic field at the centre of the loop is \(B_1 \). When the dipole moment is doubled by keeping the current constant, the magnetic field at the centre of the loop is \(B_2\). The ratio \(\frac{B_1}{B_2}\) is:
1. \(2\)
2. \(\sqrt{3}\)
3. \(\sqrt{2}\)
4. \(\frac{1}{\sqrt{2}}\)

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A charge \(q\) is spread uniformly over an insulated loop of radius \(r. \) If it is rotated with an angular velocity \(\omega\) with respect to the normal axis then the magnetic moment of the loop is:
1. \(\dfrac{3}{2}q\omega r^2\)

2. \(\dfrac{1}{2}q\omega r^2\)

3. \(q\omega r^2\)

4. \(\dfrac{4}{3}q\omega r^2\)
 
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A square loop is carrying a steady current \(I\) and the magnitude of its magnetic dipole moment is \(m\). If this square loop is changed to a circular loop and it carries the same current, the magnitude of the magnetic dipole moment of circular loop will be:
1. \( \frac{4 m}{\pi} \)
2. \(\frac{3 m}{\pi} \)
3. \(\frac{2 m}{\pi} \)
4. \(\frac{m}{\pi}\)

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A wire carrying current \(I\) is bent in the shape \(ABCDEFA\) as shown, where rectangle \(ABCDA\) and \(ADEFA\) are perpendicular to each other. If the sides of the rectangles are of lengths \(a\) and \(b\), then the magnitude and direction of magnetic moment of the loop \(ABCDEFA\) is:

                     
1. \(\sqrt{2}abI\) along \(\left [ \dfrac{\hat{j}}{\sqrt{2}}+\dfrac{\hat{k}}{\sqrt{2}} \right ]\)
2. \(\sqrt{2}abI\) along \(\left [ \dfrac{\hat{j}}{\sqrt{5}}+\dfrac{2 \hat{k}}{\sqrt{5}} \right ]\)
3. \(abI\) along \(\left [\dfrac{\hat{j}}{\sqrt{2}}+\dfrac{\hat{k}}{\sqrt{2}} \right ]\)
4. \(abI\) along \(\left [ \dfrac{\hat{j}}{\sqrt{5}}+\dfrac{2 \hat{k}}{\sqrt{5}} \right]\)

Subtopic:  Magnetic Moment |
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A circular coil has moment of inertia \(0.8~\text{kgm}^2\) around any diameter and is carrying current to produce a magnetic moment of \(20~\text{Am}^2\). The coil is kept initially in a vertical position and it can rotate freely around a horizontal diameter. When a uniform magnetic field of \(4~\text{T}\) is applied along the vertical, it starts rotating around its horizontal diameter. The angular speed the coil acquires after rotating by \(60^\circ\) will be:
1. \( 20~ \text{rad}\text{s}^{-1} \)
2. \( 20 \pi ~\text{rad} \text{s}^{-1} \)
3. \( 10 \pi ~\text{rad} \text{s}^{-1} \)
4. \( 10 ~\text{rad} \text{s}^{-1} \)
 

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An iron rod of volume \(10^{-3}~\text{m}^3\) and relative permeability \(1000\) is placed as core in a solenoid with \(10~\text{turns/cm}\). If a current of \(0.5~\text{A}\) is passed through the solenoid, then the magnetic moment of the rod will be:
1. \( 0.5 \times 10^2~\text{Am}^2 \)
2. \( 50 \times 10^2~\text{Am}^2 \)
3. \(500 \times 10^2 ~\text{Am}^2 \)
4. \(5 \times 10^2 ~\text{Am}^2 \)

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A charged particle going around in a circle can be considered to be a current loop. A particle of mass \(m\) carrying charge \(q\) is moving in a plane with speed \(v\) under the influence of a magnetic field \(\vec{B}.\) The magnetic moment of this moving particle:
1. \( \frac{m v^2 \vec{B}}{B^2} \)
2. \( -\frac{m v^2 \vec{B}}{2 \pi B^2} \)
3. \( \frac{m v^2 \vec{B}}{2 B^2} \)
4. \( -\frac{m v^2 \vec{B}}{2 B^2}\) 

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Two concentric circular loops of radii \(r_1=30\) cm and \(r_2=50\) cm are placed in \(X\text-Y\) plane as shown in the figure. A current \(I=7\) A is flowing through them in the direction as shown in figure. The net magnetic moment of this system of two circular loops is approximately:
                    
1. \(\frac{7}{2} \hat k~\text{Am}^2\)
2. \(-\frac{7}{2} \hat k~\text{Am}^2\)
3. \( 7~ \hat k~\text{Am}^2\)
4. \( -7~ \hat k~\text{Am}^2\)
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Coil \(\mathrm{A}\) of radius \(10\) cm has \(N_A\) number of turns and \(I_A\) current is flowing through it. Coil \(\mathrm{B}\) of radius \(20\) cm has \(N_B\) number of turns and \(I_B\) current is flowing through it. If the magnetic dipole moment of both the coils is the same then:
1. \( I_A N_A=4 I_B N_B \)
2. \( 4 I_A N_A= I_B N_B\)
3. \( I_A N_A=2 I_B N_B \)
4. \( 2 I_A N_A= I_B N_B \)
 
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