Mark the correct statements for a particle going on a straight line:
| (a) | if the velocity and acceleration have opposite sign, the object is slowing down. | 
| (b) | if the position and velocity have opposite sign, the particle is moving towards the origin. | 
| (c) | if the velocity is zero at an instant, the acceleration should also be zero at that instant. | 
| (d) | if the velocity is zero for a time interval, the acceleration is zero at any instant within the time interval. | 
Choose the correct option:
| 1. | (a), (b) and (c) | 2. | (a), (b) and (d) | 
| 3. | (b), (c) and (d) | 4. | all of these | 
When brakes are applied to a moving vehicle, the distance it travels before stopping is called stopping distance. It is an important factor for road safety and depends on the initial velocity \({v_0}\) and the braking capacity, or deceleration, \(-a\) that is caused by the braking. Expression for stopping distance of a vehicle in terms of \({v_0}\) and \(a\) is:
| 1. | \(\dfrac{{v_o}^2}{2a}\) | 2. | \(\dfrac{{v_o}}{2a}\) | 
| 3. | \(\dfrac{{v_o}^2}{a}\) | 4. | \(\dfrac{2a}{{v_o}^2}\) | 
A particle moves a distance \(x\) in time \(t\) according to equation \(x=(t+5)^{-1}.\) The acceleration of the particle is proportional to:
1. (velocity)\(3/2\)
2. (distance)\(2\)
3. (distance)\(-2\)
4. (velocity)\(2/3\)
| 1. | zero | 
| 2. | constant | 
| 3. | proportional to time | 
| 4. | proportional to displacement |