What is the equivalent resistance of the circuit?
1. \(6~\Omega\)
2. \(7~\Omega\)
3. \(8~\Omega\)
4. \(9~\Omega\)
If each resistance in the figure is \(9~\Omega\), then the reading of the ammeter is:
1. \(5~\text{A}\)
2. \(8~\text{A}\)
3. \(2~\text{A}\)
4. \(9~\text{A}\)
Equivalent resistance across terminals \(A\) and \(B\) will be:
1. | \(1~\Omega\) | 2. | \(2~\Omega\) |
3. | \(3~\Omega\) | 4. | \(4~\Omega\) |
The total current supplied to the circuit by the battery is:
1. \(1~\text{A}\)
2. \(2~\text{A}\)
3. \(4~\text{A}\)
4. \(6~\text{A}\)
In circuit shown below, the resistances are given in ohms and the battery is assumed ideal with emf equal to \(3\) volt. The voltage across the resistance \(R_4\) is:
1. \(0.4\) V
2. \(0.6\) V
3. \(1.2\) V
4. \(1.5\) V
A battery of emf \(E\) and internal resistance \(r\) is connected to a variable resistor \(R\) as shown below. Which one of the following is true?
1. | Potential difference across the terminals of the battery is maximum when \(R=r\). |
2. | Power delivered to the resistor is maximum when \(R=r\). |
3. | Current in the circuit is maximum when \(R=r\). |
4. | Current in the circuit is maximum when \(R>>r\). |
The current in the arm \(CD\) of the circuit will be:
1.
2.
3.
4.
Consider the circuit shown in the figure below. The current \(I_3\) is equal to:
1. \(5\) A
2. \(3\) A
3. \(-3\) A
4. \(\frac{-5}{6}\) A
In the Wheatstone's bridge (shown in the figure below) \(X=Y\) and \(A>B\). The direction of the current between \(a\) and \(b\) will be:
1. | from \(a\) to \(b\). |
2. | from \(b\) to \(a\). |
3. | from \(b\) to \(a\) through \(c\). |
4. | from \(a\) to \(b\) through \(c\). |
In the circuit given below, the emf of the cell is \(2\) volt and the internal resistance is negligible. The resistance of the voltmeter is \(80\) ohm. The reading of the voltmeter will be:
1. \(0.80\) volt
2. \(1.60\) volt
3. \(1.33\) volt
4. \(2.00\) volt