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Q. No.Monochromatic light is incident on a glass prism of angle \(A\). If the refractive index of the material of the prism is \(\mu\), a ray, incident at an angle \(\theta\), on the face \(AB\) would get transmitted through the face \(AC\) of the prism provided:
| 1. | \( \theta>\sin ^{-1}\left[\mu \sin \left({A}-\sin ^{-1}\left(\frac{1}{\mu}\right)\right)\right] \) |
| 2. | \( \theta<\sin ^{-1}\left[\mu \sin \left({A}-\sin ^{-1}\left(\frac{1}{\mu}\right)\right)\right] \) |
| 3. | \( \theta>\cos ^{-1}\left[\mu \sin \left({A}+\sin ^{-1}\left(\frac{1}{\mu}\right)\right)\right] \) |
| 4. | \( \theta<\cos ^{-1}\left[\mu \sin \left({A}+\sin ^{-1}\left(\frac{1}{\mu}\right)\right)\right]\) |
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A ray of light is incident at an angle of \(60^\circ\) on one face of a prism of angle \(30^\circ.\) The emergent ray of light makes an angle of \(30^\circ\) with the incident ray. The angle made by the emergent ray with the second face of the prism will be:
1. \(0^\circ\)
2. \(90^\circ\)
3. \(30^\circ\)
4. \(45^\circ\)
1. \(0^\circ\)
2. \(90^\circ\)
3. \(30^\circ\)
4. \(45^\circ\)
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A prism with an angle \(A=1^\circ\) and a refractive index \(\mu=1.5\) is given. A good estimate for the minimum angle of deviation (in degrees) is close to \(\dfrac{N}{10}.\) The value of \(N\) is:
1. 25
2. 20
3. 15
4. 5
1. 25
2. 20
3. 15
4. 5
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What is the expected graphical representation of the relationship between the angle of deviation \((\delta)\) and the angle of incidence \( (i )\) for a triangular prism?
| 1. |  |
2. |  |
| 3. |  |
4. |  |
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In free space, an electromagnetic wave of \(3~\text{GHz}\) of frequency strikes over the edge of an object of size \(\frac{\lambda}{100}\), where \(\lambda\) is the wavelength of the wave in free space. The phenomenon, which happens there will be:
1. Reflection
2. Refraction
3. Diffraction
4. Scattering
1. Reflection
2. Refraction
3. Diffraction
4. Scattering
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The refracting angle of a prism is \(A\) and the refractive index of the material of the prism is \(\cot(A/2)\). Then the angle of minimum deviation will be:
1. \(180^{\circ}-2A\)
2. \(90^{\circ}-A\)
3. \(180^{\circ}+2A\)
4. \(180^{\circ}-3A\)
1. \(180^{\circ}-2A\)
2. \(90^{\circ}-A\)
3. \(180^{\circ}+2A\)
4. \(180^{\circ}-3A\)
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In the given figure, the face \(AC\) of the equilateral prism is immersed in a liquid of refractive index \(n.\) For the incident angle \(60^{\circ}\) at the side \(AC,\) the refracted light beam just grazes along the face \(AC.\) The refractive index of the liquid \(n = \dfrac{ \sqrt x} {4}.\) The value of \(x\) is:
(Given a refractive index of glass \(\mu=1.5\))
1. \(15\)
2. \(22\)
3. \(24\)
4. \(27\)
(Given a refractive index of glass \(\mu=1.5\))
1. \(15\)
2. \(22\)
3. \(24\)
4. \(27\)
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Prism \(A\) has an angle of prism equal to \(6^{\circ}\) and its material has a refractive index of \(1.5\). It is used in combination with prism \(B\) of refractive index \(1.8\) to produce dispersion without deviation. The angle of prism \(B\) is:
1. \(2.53^{\circ}\)
2. \(3.52^{\circ}\)
3. \(5.73^{\circ}\)
4. \(3.75^{\circ}\)
1. \(2.53^{\circ}\)
2. \(3.52^{\circ}\)
3. \(5.73^{\circ}\)
4. \(3.75^{\circ}\)
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If the refractive index of a material of equilateral prism is \(\sqrt{2}\) , then the angle of minimum deviation of the prism is:
1. \(90^\circ\)
2. \(45^\circ\)
3. \(30^\circ\)
4. \(60^\circ\)
1. \(90^\circ\)
2. \(45^\circ\)
3. \(30^\circ\)
4. \(60^\circ\)
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A prism has a refractive index \(\cot\left(\frac{A}{2}\right),\) where \(A\) is the refracting angle of the prism. The minimum deviation due to this prism is:
1. \(\pi-3A\)
2. \(\pi-2A\)
3. \(A\)
4. \(\frac{A}{2}\)
1. \(\pi-3A\)
2. \(\pi-2A\)
3. \(A\)
4. \(\frac{A}{2}\)
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