Consider the following Statements A and B and identify the correct answer:
                   
A. For a solar-cell, the \(I\text-V\) characteristics lies in the IV quadrant of the given graph.
B. In a reverse-biased pn junction diode, the current measured in (\(\mu \text{A}\)), is due to majority charge carriers.
 
1. A is incorrect but B is correct.
2. Both A and B are correct.
3. Both A and B are incorrect.
4. A is correct but B is incorrect.
Subtopic:  Applications of PN junction |
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A logic circuit provides the output \(Y\) as per the following truth table:
\(A\) \(B\) \(Y\)
0
0
1
1
0
1
0
1
1
0
1
0
The expression for the output \(Y\) is : 
1. \(A \cdot \overline{B}+\overline{A} \)
2. \(\overline{B} \)
3. \(B \)
4. \(A \cdot B+\overline{A}\)
Subtopic:  Logic gates |
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The output (\(Y\)) of the given logic gate is similar to the output of an/a: 
                    
1. \(\text{NOR}\) gate 
2. \(\text{OR}\) gate 
3. \(\text{AND}\) gate 
4. \(\text{NAND}\) gate 
Subtopic:  Logic gates |
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Choose the correct circuit which can achieve the bridge balance :
1. 2.
3. 4.
Subtopic:  PN junction |
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A solar cell is a:
1. forward biased zener diode.
2. type of light-emitting diode.
3. diode working on the principle of photo-voltaic effect.
4. type of photo-diode with external biasing.
Subtopic:  Applications of PN junction |
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The correct input \((A,B)\) - output \((Y)\) combination for the given circuit is:
                 
1. \(A=1,B=1,Y=1\)
2. \(A=0,B=1,Y=1\)
3. \(A=1,B=0,Y=0\)
4. \(A=0,B=0,Y=1\)
Subtopic:  Logic gates |
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Zener diode works:
1. in forward bias only.
2. in reverse bias only.
3. as a voltage regulator in forward bias and as a simple pn junction diode in reverse bias.
4. as a voltage regulator in reverse bias and as a simple pn junction diode in forward bias.
Subtopic:  Applications of PN junction |
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The \(I\text-V\) characteristics shown above are exhibited by a:
1. light-emitting diode 2. zener-diode
3. photodiode 4. solar cell
Subtopic:  Applications of PN junction |
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When the output of an OR gate is applied as input to a NOT gate, then the combination acts as a:
1. NAND gate
2. NOR gate
3. AND gate
4. OR gate
Subtopic:  Logic gates |
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The output \(Y\) for the inputs \(A\) and \(B\) of the given logic circuit is:
       
1. \(A\cdot B\)
2. \(\overline{A}\cdot\overline{B}\)
3. \(A+B\)
4. \(\overline{A}+\overline{B}\)

 
Subtopic:  Logic gates |
 63%
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