A system consists of three masses \(m_1,\) \(m_2,\) and \(m_3\) connected by a string passing over a pulley \(\mathrm{P}.\) The mass \(m_1\) hangs freely, and \(m_2\) and \(m_3\) are on a rough horizontal table (the coefficient of friction \(=\mu.\)) The pulley is frictionless and of negligible mass. The downward acceleration of mass \(m_1\) is:
(Assume \(m_1=m_2=m_3=m\) and \(g\) is the acceleration due to gravity.)

A block of mass \(m\) is in contact with the cart \((C)\) as shown in the figure. 
                    
The coefficient of static friction between the block and the cart is \(\mu.\) The acceleration \(a\) of the cart that will prevent the block from falling satisfies:
1. \(a > \dfrac{mg}{\mu}\)
2. \(a > \dfrac{g}{\mu m}\)
3. \(a \ge \dfrac{g}{\mu}\)
4. \(a < \dfrac{g}{\mu}\)

A block of mass \(m\) lying on a rough horizontal plane is acted upon by a horizontal force \(P\) and another force \(Q\) inclined at an angle \(\theta\) to the vertical. The block will remain in equilibrium if the coefficient of friction between it and the surface is: 

                        
1. \(\frac{(P+Q\sin\theta)}{(mg+Q\cos\theta)}\)

2. \(\frac{(P\cos\theta+Q)}{(mg-Q\sin\theta)}\)

3. \(\frac{(P+Q\cos\theta)}{(mg+Q\sin\theta)}\)

4. \(\frac{(P\sin\theta-Q)}{(mg-Q\cos\theta)}\)

A plank with a box on it at one end is gradually raised at the other end. As the angle of inclination with the horizontal reaches \(30^{\circ}\), the box starts to slip and slides \(4.0\) m down the plank in \(4.0\) s. The coefficients of static and kinetic friction between the box and the plank, respectively, will be:
                         

If \(\mu\) between block \(A\) and inclined plane is \(0.5\) and that between block \(B\) and the inclined plane is \(0.8,\) then the normal reaction between blocks \(A\) and \(B\) will be:
                       
1. \(180~\text N\) 
2. \(216~\text N\) 
3. \(0\)
4. none of these

Two blocks of masses \(2\) kg and \(3\) kg placed on a horizontal surface are connected by a massless string. If \(3~\text{kg}\) is pulled by \(10\) N as shown in the figure, then the force of friction acting on the \(2~\text{kg}\) block will be:
(Take \(g=10~\text{m/s}^2\))$\mathrm{}$