When 5 g of non-volatile non-electrolyte solute is dissolved in 100 g of a certain solvent, the freezing point of the solvent decreases by 0.25 K. The molar mass of the solute is:
\([\text{K}_f \) of the given solvent \( =1.2 \mathrm{K ~kg}~ \mathrm{mol}^{-1}] \)
1. \(242.8 \mathrm{~g} \mathrm{~mol}^{-1}\) 2. \(238.2 \mathrm{~g} \mathrm{~mol}^{-1}\)
3. \(241.8 \mathrm{~g} \mathrm{~mol}^{-1}\) 4. \(240.0 \mathrm{~g} \mathrm{~mol}^{-1}\)
Subtopic:  Depression of Freezing Point |
 79%
From NCERT
NEET - 2024
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The freezing point of depression constant (Kf ) of benzene is 5.12 K kg mol–1. The freezing point depression for the solution of molality 0.078 m containing a non-electrolyte solute in benzene is:
(rounded off up to two decimal places)
1. 0.80 K
2. 0.40 K
3. 0.60 K
4. 0.20 K

Subtopic:  Depression of Freezing Point |
 87%
From NCERT
NEET - 2020
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The freezing point depression constant for water is 1.86 oC m-1. If 5.00 g Na2SOis dissolved in 45.0 g H2O,
the freezing point is changed by -3.82 oC. The Van’t Hoff factor for Na2SO4 is:

1. 2.63 2. 3.11
3. 0.381 4. 2.05
Subtopic:  Depression of Freezing Point |
 69%
From NCERT
AIPMT - 2011
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A 0.1 molal aqueous solution of a weak acid (HA) is 30 % ionized. If Kf for water is 1.86 °C/m, the freezing point of the solution will be:

1. –0.24 °C  2. –0.18 °C
3. –0.54 °C  4. –0.36 °C
Subtopic:  Depression of Freezing Point |
 66%
From NCERT
AIPMT - 2011
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A solution of sucrose (molar mass = 342 g mol–1) has been prepared by dissolving 68.5 g of sucrose in 1000 g of water. The freezing point of the solution obtained will be: 
(kf for water = 1.86 K kg mol–1)
1. –0.372 oC
2. –0.520 oC
3. +0.372 oC
4. –0.570 oC

Subtopic:  Depression of Freezing Point |
 82%
From NCERT
AIPMT - 2010
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A 0.0020 m aqueous solution of an ionic compound Co(NH3)5(NO2)Cl freezes at -0.0073 oC. The number of moles of ions that 1 mol of ionic compound produces on being dissolved in water will be:
(Kf = -1.86 oC/m)

1. 2 2. 3
3. 4 4. 1
Subtopic:  Depression of Freezing Point | Van’t Hoff Factor |
 67%
From NCERT
AIPMT - 2009
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0.5 molal aqueous solution of a weak acid (HX) is 20 % ionised. The lowering in the freezing point of the solution will be:
[Kf for water = 1.86 K kg mol-1]

1. -1.12 K

2. 0.56 K

3. 1.12 K

4. -0.56 K

Subtopic:  Depression of Freezing Point | Van’t Hoff Factor |
 55%
From NCERT
AIPMT - 2007
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A solution of urea (molar mass 56 g mol–1) boils at 100.18 ºC at atmospheric pressure. If Kf and Kb for water are 1.86 and 0.512 K kg mol–1 respectively, the above solution will freeze at:

1. –6.54 ºC

2. –0.654 ºC

3. 6.54 ºC

4. 0.654 ºC

Subtopic:  Elevation of Boiling Point | Depression of Freezing Point |
 75%
From NCERT
AIPMT - 2005
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