Consider the following compounds,
A. n-Butane
B. 2-Methylbutane
C. n-Pentane
D. 2, 2-Dimethylpropane
The correct decreasing order of their boiling points is-
1. A > B > C > D
2. B > C > D > A
3. C > B > D > A
4. D > C > B > A
Which of the following will not show geometrical isomerism?
| 1. | |
2. | |
| 3. | ![]() |
4. | ![]() |
Match the hydrocarbons in Column I with the boiling points given in Column II.
| A. n-Pentane | 1. 282.5 K |
| B. Isopentane | 2. 309 K |
| C. Neopentane | 3. 301 K |
Codes
| Options: | A | B | C |
| 1. | 2 | 3 | 1 |
| 2. | 1 | 2 | 3 |
| 3. | 2 | 1 | 3 |
| 4. | 3 | 2 | 1 |
Given below are two statements:
| Assertion (A): | Among isomeric pentanes, 2,2-dimethylpropane has the highest boiling point. |
| Reason (R): | Branching does not affect the boiling point. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | Both (A) and (R) are False. |
| 4. | (A) is True but (R) is False. |
The molecules having dipole moment are ________
a. 2,2-Dimethylpropane
b. trans-Pent-2-ene
c. cis-Hex-3-ene
d. 2,2,3,3 - Tetramethylbutane
Choose the correct option
1. (a, b)
2. (b, c)
3. (c, d)
4. (a, c)