The graph between vs log p is given below:
What is the value of the slope?
1.
2. n
3.
4.
In the Freundlich adsorption isotherm, the value of 1/n is:
1. Between 0 and 1 in all cases.
2. Between 2 and 4 in all cases.
3. 1 in the case of physical adsorption.
4. 1 in the case of chemisorption.
An adsorption isotherm is a plot between:
1. | The extent of adsorption \(({x \over m})\) against the pressure of gas (P) at constant V. |
2. | The extent of adsorption \(({x \over m})\) against the pressure of gas (P) at constant T. |
3. | The extent of absorption \(({x \over m})\) against the volume of gas (V) at constant P. |
4. | The extent of absorption \(({x \over m})\) against the pressure of gas (P) at constant T. |
The equation that represents a Freundlich adsorption isotherm is:
1.
2.
3.
4.
The correct curve for Freundlich's adsorption isotherm is:
1. | 2. | ||
3. | 4. |
Consider the following graph between (extent of adsorption) and pressure:
What is the correct relation between T1, T2, and T3?
1. T3 < T2 > T1
2. T1 < T2 < T3
3. T1 > T2 > T3
4. None of the above
According to Freundlich adsorption isotherm, at high pressure, the value of is -
1. Directly proportional to the pressure.
2. Inversely proportional to the pressure.
3. Directly proportional to the square of the pressure.
4. Independent of the pressure.
In an adsorption experiment, a graph between log(x/m) versus log P was found to be linear with a slope of 45. The intercept on the y-axis was found to be 0.3. What will be the value of x/m at a pressure of 3 atm for the Freundlich adsorption isotherm when 1/n remains constant?
[Antilog 0.3 = 2]
1. 2
2. 4
3. 6
4. 5