An organic compound with the molecular formula C9H10O forms a 2,4-DNP derivative, reduces Tollens’ reagent, and undergoes the Cannizzaro reaction. On vigorous oxidation, it gives 1,2-benzenedicarboxylic acid. This organic compound will be:
1. | 2-Methyl benzaldehyde | 2. | 2-Hydroxy benzaldehyde |
3. | 2-Ethyl benzaldehyde | 4. | 4-Ethyl benzaldehyde |
The major product formed when cyclohexanecarbaldehyde reacts with PhMgBr and H3O+ is:
1. | 2. | ||
3. | 4. | None of these |
What is the major product of the reaction between cyclohexanecarbaldehyde and Tollens' reagent?
1. | 2. | ||
3. | 4. | None of these |
The compounds that undergoes the Cannizzaro reaction are:
(i) Methanal
(ii) 2-Methylpentanal
(iii) Benzaldehyde
(iv) Benzophenone
1. (i)
2. (ii)
3. (i), (iii)
4. (i), (ii), (iii)
There is only one –NH2 group involved in semicarbazone formation out of two –NH2 group. It is due to:
1. Resonance of one type of –NH2 group
2. Inductive effect of one type of –NH2 group
3. Hyperconjugation of one type of –NH2 group
4. Reverse hyperconjugation of one type of -NH2 group
Chemical test(s) to distinguish between the Propanal and Propanone is :
1. | Tollen’s test
|
2. | Fehling’s test
|
3. | Iodoform test
|
4. | All of these |
Chemical test(s) used to distinguish between Acetophenone and Benzophenone is :
1. Tollen’s test
2. Fehling’s test
3. Iodoform test
4. All of the above
A chemical test to distinguish between Phenol and Benzoic acid is :
1. Tollen’s test
2. Fehling’s test
3. Iodoform test
4. Ferric chloride test